[LLVMdev] how can I create an SSE instrinsics sqrt?

[zhi chen]

However, there is a new problem now. I can load the pass and use the
CreateFSqrt
to create a new vector version sqrt.

%vsqrt = call <2 x double> @llvm.x86.sse2.sqrt.pd.v2f64(<2 x double> %1)

However, if I use the %vsqrt in the later instruction %add1 = fadd <2 x
double> %vsqrt, <2 x double> %2, I will get the following error:

%vsqrt = callopt: ../llvm-3.3.src/include/llvm/Support/Casting.h:237:
typename llvm::enable_if<llvm::is_same<Y, typename
llvm::simplify_type<From>::SimpleType>, typename llvm::cast_retty<X,
Y*>::ret_type>::type llvm::cast(Y*) [with X = llvm::PointerType; Y =
llvm::Type; typename llvm::enable_if<llvm::is_same<Y, typename
llvm::simplify_type<From>::SimpleType>, typename llvm::cast_retty<X,
Y*>::ret_type>::type = llvm::PointerType*]: Assertion `isa<X>(Val) &&
"cast<Ty>() argument of incompatible type!"' failed. Any hint about this
error?

Thanks,
Zhi


On Fri, Apr 17, 2015 at 8:52 PM, zhi chen <zchenhn at gmail.com> wrote:

> Thanks, Shahid. It is fixed now.
>
> On Fri, Apr 17, 2015 at 8:50 PM, Shahid, Asghar-ahmad <
> Asghar-ahmad.Shahid at amd.com> wrote:
>
>>  Hi zhi,
>>
>>
>>
>> You have to also pass the value type to getDecalaration() API such as
>>
>>
>>
>> Value* sqrtv = Intrinsic::getDeclaration(M, Intrinsic::x86_sse2_sqrt_pd,
>> v->getType());
>>
>>
>>
>> Regards,
>>
>> Shahid
>>
>>
>>
>> *From:* llvmdev-bounces at cs.uiuc.edu [mailto:llvmdev-bounces at cs.uiuc.edu] *On
>> Behalf Of *zhi chen
>> *Sent:* Saturday, April 18, 2015 5:52 AM
>> *To:* LLVM Dev
>> *Subject:* [LLVMdev] how can I create an SSE instrinsics sqrt?
>>
>>
>>
>> I want to create a vector version sqrt as the following.
>>
>>
>>
>> Value *Approx::CreateFSqrt(IRBuilder<> &builder, Value *v, const char*
>> Name) {
>>
>>   Type *tys[] = {v->getType()};
>>
>>   Module* M = currF->getParent();
>>
>>   Value* sqrtv = Intrinsic::getDeclaration(M,
>> Intrinsic::x86_sse2_sqrt_pd);
>>
>>   CallInst *CI = builder.CreateCall(sqrtv, v, Name);
>>
>>
>>
>>   return CI;
>>
>> }
>>
>>
>>
>> Here is Value *v is <2 x double>
>>
>> However, it outputs Assertion `isa<X>(Val) && "cast<Ty>() argument of
>> incompatible type! any idea?
>>
>
>
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