[LLVMdev] how can I create an SSE instrinsics sqrt?
zhi chen
zchenhn at gmail.com
Fri Apr 17 20:52:57 PDT 2015
Thanks, Shahid. It is fixed now.
On Fri, Apr 17, 2015 at 8:50 PM, Shahid, Asghar-ahmad <
Asghar-ahmad.Shahid at amd.com> wrote:
> Hi zhi,
>
>
>
> You have to also pass the value type to getDecalaration() API such as
>
>
>
> Value* sqrtv = Intrinsic::getDeclaration(M, Intrinsic::x86_sse2_sqrt_pd,
> v->getType());
>
>
>
> Regards,
>
> Shahid
>
>
>
> *From:* llvmdev-bounces at cs.uiuc.edu [mailto:llvmdev-bounces at cs.uiuc.edu] *On
> Behalf Of *zhi chen
> *Sent:* Saturday, April 18, 2015 5:52 AM
> *To:* LLVM Dev
> *Subject:* [LLVMdev] how can I create an SSE instrinsics sqrt?
>
>
>
> I want to create a vector version sqrt as the following.
>
>
>
> Value *Approx::CreateFSqrt(IRBuilder<> &builder, Value *v, const char*
> Name) {
>
> Type *tys[] = {v->getType()};
>
> Module* M = currF->getParent();
>
> Value* sqrtv = Intrinsic::getDeclaration(M, Intrinsic::x86_sse2_sqrt_pd);
>
> CallInst *CI = builder.CreateCall(sqrtv, v, Name);
>
>
>
> return CI;
>
> }
>
>
>
> Here is Value *v is <2 x double>
>
> However, it outputs Assertion `isa<X>(Val) && "cast<Ty>() argument of
> incompatible type! any idea?
>
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