[llvm-bugs] [Bug 51360] New: SimplifyCFGPass hoists unsafe instruction and caused undefined behaviour
via llvm-bugs
llvm-bugs at lists.llvm.org
Thu Aug 5 08:31:26 PDT 2021
https://bugs.llvm.org/show_bug.cgi?id=51360
Bug ID: 51360
Summary: SimplifyCFGPass hoists unsafe instruction and caused
undefined behaviour
Product: clang
Version: unspecified
Hardware: PC
OS: Windows NT
Status: NEW
Severity: normal
Priority: P
Component: C
Assignee: unassignedclangbugs at nondot.org
Reporter: Zhi.Zhuang at mediatek.com
CC: blitzrakete at gmail.com, dgregor at apple.com,
erik.pilkington at gmail.com, llvm-bugs at lists.llvm.org,
richard-llvm at metafoo.co.uk
Reduced test case:
#include <stdint.h>
int32_t foo(int32_t a, int32_t b) {
return (a>0 && b>0 && a>INT32_MAX-b) || (a<0 && b<0 && a<INT32_MAX-b) ? 0 :
(a+b);
}
and using sha <2e75986a21e5>, command is "clang -O3 -S -mllvm -print-after-all
test.c"
Before second SimplifyCFGPass, the IR was like follows:
2:
%3 = icmp sgt i32 %0, 0
%4 = icmp sgt i32 %1, 0
%5 = select i1 %3, i1 %4, i1 false
br i1 %5, label %6, label %9
6: ; preds = %2
%7 = sub nsw i32 2147483647, %1
The sub nsw will only be executed when %1 was positive since that was the
condition when %6 was branched, so sub will not overflow and nsw keyword makes
sense.
But after second SimplifyCFGPass, that sub was hoisted to first block:
2:
%3 = icmp sgt i32 %0, 0
%4 = icmp sgt i32 %1, 0
%5 = select i1 %3, i1 %4, i1 false
%6 = sub nsw i32 2147483647, %1
%7 = icmp slt i32 %6, %0
%8 = select i1 %5, i1 %7, i1 false
br i1 %8, label %18, label %9
This %6=sub nsw does not makes sense anymore since %1 maybe negative, and this
block branching using the result of %6 and may cause undefined behavior
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