[llvm-bugs] [Bug 43010] New: __builtin_assume causes a call to a function marked as __attribute__((const)) or ((pure)) to be needlessly propagated
via llvm-bugs
llvm-bugs at lists.llvm.org
Thu Aug 15 11:31:22 PDT 2019
https://bugs.llvm.org/show_bug.cgi?id=43010
Bug ID: 43010
Summary: __builtin_assume causes a call to a function marked as
__attribute__((const)) or ((pure)) to be needlessly
propagated
Product: libraries
Version: trunk
Hardware: All
OS: All
Status: NEW
Severity: enhancement
Priority: P
Component: Scalar Optimizations
Assignee: unassignedbugs at nondot.org
Reporter: mike.k at digitalcarbide.com
CC: llvm-bugs at lists.llvm.org
In a situation when a call to an external __attribute__((const)) or
__attribute__((pure)) is encapsulated in a __builtin_assume, and then called,
the function is still called despite having no side-effects and the result
value being known.
extern int foo() __attribute__((const));
extern void oof();
void bar() {
__builtin_assume(foo() == 1);
if (foo() == 1) {
oof();
}
}
results in the following x86-64 assembly with -03:
bar(): # @bar()
push rax
call foo()
pop rax
jmp oof() # TAILCALL
The `call foo()`, as stated, is unnecessary.
If the code is refactored to use a temporary variable for the result, as such:
extern int foo() __attribute__((const));
extern void oof();
void bar() {
int foo_result = foo();
__builtin_assume(foo_result == 1);
if (foo_result == 1) {
oof();
}
}
It then produces the expected output:
bar(): # @bar()
jmp oof() # TAILCALL
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