[cfe-dev] CXXRecordDecl Name
Daniel Dilts
diltsman at gmail.com
Tue Jul 1 09:21:36 PDT 2014
If I have this code then everything works. If I get rid of the forward
declaration, then any method returns an empty string. Is the forward
declaration mandatory when defining the class like this?
namespace N {
class BaseClass1;
}
class N::BaseClass1 {
public:
BaseClass1(int i);
BaseClass1(const BaseClass1 &right);
virtual ~BaseClass1();
BaseClass1 &operator=(const BaseClass1 &right);
}
On Mon, Jun 30, 2014 at 3:35 PM, Reid Kleckner <rnk at google.com> wrote:
> Try getDeclName(), getNameAsString(), or others. getName() only works if
> the name is a simple identifier:
>
> /// getName - Get the name of identifier for this declaration as a
> StringRef.
> /// This requires that the declaration have a name and that it be a
> simple
> /// identifier.
> StringRef getName() const {
> assert(Name.isIdentifier() && "Name is not a simple identifier");
> return getIdentifier() ? getIdentifier()->getName() : "";
> }
>
>
>
> On Mon, Jun 30, 2014 at 3:21 PM, Daniel Dilts <diltsman at gmail.com> wrote:
>
>> I am attempting to get the name of a CXXRecordDecl that I have identified
>> with an AST matcher. I am using Class->getName().str() to get the class
>> name.
>>
>> namespace N {
>> class SomeNonInterface {
>> virtual void func1() = 0;
>> virtual void func2() {}
>> };
>> }
>>
>> It works great for the above code. Gives me "SomeNonInterface" as the
>> name.
>>
>> class N::BaseClass1 {
>> public:
>> BaseClass1(int i);
>> BaseClass1(const BaseClass1 &right);
>> virtual ~BaseClass1();
>> BaseClass1 &operator=(const BaseClass1 &right);
>> };
>>
>> For the above code it gives me "" as the name.
>>
>> How would I get the class name so that it works in all cases, even if the
>> name in the declaration/definition is namespace qualified? Or...did I hit
>> a case that isn't legal?
>>
>> _______________________________________________
>> cfe-dev mailing list
>> cfe-dev at cs.uiuc.edu
>> http://lists.cs.uiuc.edu/mailman/listinfo/cfe-dev
>>
>>
>
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