[clang] [llvm] [X86] Enhance kCFI type IDs with a 3-bit arity indicator. (PR #117121)
Scott Constable via cfe-commits
cfe-commits at lists.llvm.org
Wed Nov 27 15:26:55 PST 2024
scottconstable wrote:
> This is not a Rust concern, but re-reading the initial post, it _looks_ like your own statistics suggest that consuming 3 bits for arity costs more than it buys you. As stated, (didn't check your math, just going off what you said) prior to your change, we expect 0.01383765 collisions in your sample environment.
If you had checked my math, you would have noticed that the values in the right-hand column were not exactly correct! I found and fixed a but in my Excel code and updated that chart, but the numbers didn't change by much.
> After your change, we expect to have the _sum_ of your right hand column in collisions, which comes out to 0.0266774 - nearly double the rate of collisions we have with the basic implementation. In fact, I think that any scheme like this will always going to increase the number of overall collisions, given that the arity is implicitly hashed into the representation already.
Your analysis is correct that the total number of expected collisions would increase from 0.01375771 to 0.02660650 (with the updated statistics).
> The main reason I could see to consider this is if for some reason a cross-arity collision is more dangerous than a same-arity collision in terms of exploitability, which I can't immediately argue, but perhaps you have something for this that was just assumed in the initial post?
I think that a cross-arity collision is clearly more dangerous than a same-arity collision. This is what I had written in the PR description:
> > The current 32-bit kCFI hash does not prevent, for example, a 2-arity fptr from calling a 3-arity target if the kCFI hashes collide. If this were to happen, then potentially malicious stale/dead data in RDX at the call site could suddenly become live as the third parameter at the call target.
Including the arity in the hash does prevent or even reduce the likelihood that a cross-arity collision will occur, if the hash function is uniform. Suppose that two function types' hashes collide (under the current 32-bit hash scheme). The probability that the arities differ is equal to 1 minus the probability that the arities agree:
1 - ((32/10903)*(31/10902) + (2492/10903)*(2491/10902) + ... + (148/10903)*(147/10902)) = 0.75901
Thus, if there is a hash collision, there is roughly a 76% chance that it will be a cross-arity collision.
https://github.com/llvm/llvm-project/pull/117121
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