[PATCH] D149009: [Sema]Select correct lexical context during template instantiate

Erich Keane via Phabricator via cfe-commits cfe-commits at lists.llvm.org
Wed Apr 26 07:27:56 PDT 2023


erichkeane added inline comments.


================
Comment at: clang/lib/Sema/SemaTemplateDeduction.cpp:3598
+      FD->isDefined(FDFriend, true) &&
+      FDFriend->getFriendObjectKind() != Decl::FriendObjectKind::FOK_None) {
+    // if Function defined by inline friend, use inline fried as DeclContext
----------------
HerrCai0907 wrote:
> erichkeane wrote:
> > HerrCai0907 wrote:
> > > erichkeane wrote:
> > > > So in what case would the currently-instantiated definition NOT also be a friend?  I would think this last condition should be able to be an assert instead.
> > > Last condition cannot be an assert, define and declare in difference place is common case, what we need to identifier in here is inlined friend define.
> > Can you be more clear here?  WHEN can a definition and declaration NOT have the same friend object kind?  THAT is probably incorrect a bug.
> Sorry I cannot get the point. 
> Here I have 3 conditions:
> 1. FD->getFriendObjectKind() == Decl::FriendObjectKind::FOK_None
> FD(declaration) is not friend object.
> 2. FD->isDefined(FDFriend, true)
> get FDFriend(definition) from FD(declaration).
> 3. FDFriend->getFriendObjectKind() != Decl::FriendObjectKind::FOK_None)
> FDFriend(definition) is friend object.
> 
> matching those 3 condition and then we can say FDFriend is a inline friend like
> ```
> template <class F1> int foo(F1 X); // FD
> template <int A1> struct A {
> template <class F1> friend int foo(F1 X) { return A1; } // FDFriend
> };
> ```
Ok, my question is: WHEN is #3 "false" but #1 and #2 are "true"?  It should not be possible for #1 to be "true" but #3 to be "false", as far as I know.


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