[llvm-bugs] [Bug 44424] Simple C program produces different output if compiled with -O1 instead of -O0
via llvm-bugs
llvm-bugs at lists.llvm.org
Wed Jan 1 06:57:13 PST 2020
https://bugs.llvm.org/show_bug.cgi?id=44424
Roman Lebedev <lebedev.ri at gmail.com> changed:
What |Removed |Added
----------------------------------------------------------------------------
Resolution|--- |INVALID
CC| |lebedev.ri at gmail.com
Status|NEW |RESOLVED
--- Comment #1 from Roman Lebedev <lebedev.ri at gmail.com> ---
(In reply to Dirk Hoffmann from comment #0)
> Test program: main.cpp
>
>
> #include <stdint.h>
> #include <stdio.h>
>
> bool foo(uint32_t x, uint32_t y)
> {
> uint32_t z = (uint16_t)x * (uint16_t)y;
This line contains UB - the multiplication does not happen in uint16_t,
but the uint16_t values are promoted to int, so this is signed overflow.
https://godbolt.org/z/wPp7Xq
> return z & 0x80000000;
> }
>
> int main(int argc, char *argv[])
> {
> printf("%d\n", foo(0x7FFFF, 0x7FFFF));
> }
>
>
>
> Compiler:
>
> Apple clang version 11.0.0 (clang-1100.0.33.8)
> Target: x86_64-apple-darwin18.7.0
> Thread model: posix
>
> Output:
>
> > clang -O0 main.cpp; ./a.out
> 1
>
> > clang -O1 main.cpp; ./a.out
> 0
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