[cfe-dev] Recovering the unqualified class name from a function parameter

[Victor Vicente de Carvalho]

This did the trick:

LangOptions lo;
PrintingPolicy pp(lo);
pp.SuppressTagKeyword = true;

std::string str =
(*param)->getType().getNonReferenceType().getUnqualifiedType().getAsString(pp);

Thanks!


2012/11/2 Victor Vicente de Carvalho <victor.v.carvalho at gmail.com>

> That managed to remove the const and the reference type, but when I try to
> use the "getAsString" method it returns to me "class Type". I could
> manually remove the "class  " part, just to know if there is a way to do in
> a non hackish way.
>
>
> Thanks
>
>
> 2012/11/2 Eli Friedman <eli.friedman at gmail.com>
>
>> On Fri, Nov 2, 2012 at 2:45 PM, Victor Vicente de Carvalho
>> <victor.v.carvalho at gmail.com> wrote:
>> > Hello,
>> >
>> > I'm trying without success to recover the unqualified name for a type
>> while
>> > parsing a CXXMethodDecl. The first problem is that the Type class
>> doesn't
>> > have a getNameAsString, or getAsString. The second problem is that even
>> > getting the unqualified type and dumping it still resolves to qualified
>> > types.
>> >
>> > Suppose I have a parameter on a function named as "const ClassType& x":
>> >
>> > all of those:
>> >  (*param)->getType()->getUnqualifiedDesugaredType()->dump();
>> >  (*param)->getType().getUnqualifiedType()->dump();
>> >  (*param)->getType()->dump();
>> >
>> > returns const ClassType &identifier when dumping.
>>
>> Try (*param)->getType().getNonReferenceType().getUnqualifiedType().dump()
>> .
>>
>> -Eli
>>
>
>
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