[llvm-dev] Removing a redundant unconditional branch
Hiroshi Yamauchi via llvm-dev
llvm-dev at lists.llvm.org
Fri Feb 7 08:59:04 PST 2020
Perhaps, you'd need to also check that the block %15 has only one
predecessor and has no other users?
Posting the error message might help.
On Thu, Feb 6, 2020 at 8:17 PM Charitha Saumya via llvm-dev <
llvm-dev at lists.llvm.org> wrote:
> Hi,
>
> I want to remove a redundant unconditional branch from a Function. In the
> following example I want to remove br label %26 and merge them to a
> single basic block.
>
> ; <label>:9: ; preds = %7
> %10 = fadd float %5, %8
> %11 = fmul float %5, %8
> %12 = fadd float %10, %11
> %13 = fdiv float %5, %8
> %14 = fadd float %13, %12
> br label %15
> ; <label>:15: ; preds = %9
> br label %26
>
> I tried to do this as follow but ended up getting runtime error. Can
> someone help?
>
> Thanks
>
> Charitha
> for(auto it1 = F.begin(); it1 != F.end(); it1++){
> BasicBlock& bb = *it1;
> auto BI = dyn_cast<BranchInst>(bb.getTerminator());
> if(BI && BI->isUnconditional() && bb.size() == 1){
>
> for (BasicBlock *pred : predecessors(&bb)) {
> auto predBI = dyn_cast<BranchInst>(pred->getTerminator());
> if(predBI && predBI->isUnconditional()){
> predBI->setSuccessor(0, bb.getSingleSuccessor());
> BI->dropAllReferences();
> BI->removeFromParent();
> }
> }
> }
>
> }
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