[llvm-dev] intra vs inter module LTO

Mehdi AMINI via llvm-dev llvm-dev at lists.llvm.org
Tue Jan 1 10:27:02 PST 2019


Hi,


On Mon, Dec 31, 2018 at 9:58 AM A. Ilchinger via llvm-dev <
llvm-dev at lists.llvm.org> wrote:

> It is quite common for larger project to split the source tree into
> multiple libraries, which are built statically and linked together at
> the end. This practise also has advantages building tests, because only
> the library for the classes under test has to be linked.
>
> When it comes to LTO, I understand that it works when multiple .o files
> are linked together, doing its magic hopefully optimizing the resulting
> binary, be it a library or an executable. This is great for optimizing
> the different parts of a larger project individually. I don't know if
> there is an official term for that, but I'd call it intra-module LTO,
>

A "Module" is a single .o in LLVM (usually). So LTO is always about
cross-module optimizations.

The closer to use to describe the scope of optimization is probably a DSO
(Dynamic Shared Object): i.e. a shared library (.so) or the final binary.


> where module basically means a binary target, be it the only one or
> just an intermediate.
>
> I'd like to know if LTO also works in the second step, when multiple .a
> libraries and potentially other .o files are linked together to the
> final binary. So can LTO also work successfully between modules (being
> inter-module).
>

.a are really just an archive containing multiple .o, after the linker
decide to pull some .o files out of a .a archive (there are some rule
around this), there is no difference with .o directly passed on the command
line as far as I know.


> And if it is possible, do I have to pay attention to some compiler
> flags, linker options, etc., or does it work out-of-the-bos with -flto?
>
>
So LTO work just as fine with .a, with one caveat: the tool used to create
the .a has to be compatible with LLVM bitcode (i.e. use llvm-ar instead of
ar to create the archive) otherwise the .a creation may fail or the link
step may fail.

Best,

-- 
Mehdi
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