[llvm-dev] proposal for optimization method
Eli Friedman via llvm-dev
llvm-dev at lists.llvm.org
Thu Feb 21 11:55:47 PST 2019
There’s a work-in-progress patch for the case r=0: https://reviews.llvm.org/D50222 . (Not sure what the current status of that patch is.)
-Eli
From: llvm-dev <llvm-dev-bounces at lists.llvm.org> On Behalf Of Craig Topper via llvm-dev
Sent: Wednesday, February 20, 2019 9:27 PM
To: or dv <dvoreader at gmail.com>
Cc: llvm-dev <llvm-dev at lists.llvm.org>
Subject: [EXT] Re: [llvm-dev] proposal for optimization method
It looks like gcc already does something like this. https://godbolt.org/z/JWljkL
~Craig
On Wed, Feb 20, 2019 at 8:45 PM or dv via llvm-dev <llvm-dev at lists.llvm.org<mailto:llvm-dev at lists.llvm.org>> wrote:
Hello everyone, I discovered a way to perform optimization on the following code (I gave an example that uses 32bit integer, but it works with any size.):
const uint32 d,r;//d is an odd number
//d is the divisor, r is the remainder
bool check_remainder(uint32 x)
{
return x%d==r;
}
if we know d and r at compile time, and d is an odd integer, we can use modular multiplicative inverse to bypass the division operation.
I wrote the following code to calculate the M.M.I of a number over 2^b. I give anyone the permission to use it (unlicensed).
uint64_t find_mod_mul_inverse(uint64_t x, uint64_t bits)
{
if (bits > 64 || ((x&1)==0))
return 0;// invalid parameters
uint64_t mask;
if (bits == 64)
mask = -1;
else
{
mask = 1;
mask<<=bits;
mask--;
}
x&=mask;
uint64_t result=1, state=x, ctz=0;
while(state!=1ULL)
{
ctz=__builtin_ctzll(state^1);
result|=1ULL<<ctz;
state+=x<<ctz;
state&=mask;
}
return result;
}
now consider the following steps:
from the 2 constants (d and r) we create 3 constants (with the same bit length):
constants uint32 s,u,mmi;
mmi = find_mod_mul_inverse(d,32);
s = (r*mmi);
u = (UINT32_MAX-r)/d; // UINT32_MAX corresponds to pow(2,32)-1.
the idea behind these constants is the following formula:
mmi_of(d)*x=x/d+(x%d)*mmi_of(d)
now after we generated the constants, we will just emit the following code instead of the former:
bool check_remainder(uint32 x)
{
return ((x*mmi)-s)<=u;
}
Anyway, I looked at the file IntegerDivision.cpp, it seems to me that this new optimization is more effective then the optimization used there. However, I have no experience with compiler development, so I can just give you my idea. if further explanation is needed, just ask. I tested my method and it gives the correct results.
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