[LLVMdev] Clang devirtualization proposal
Philip Reames
listmail at philipreames.com
Fri Jul 31 17:03:14 PDT 2015
On 07/31/2015 04:05 PM, Piotr Padlewski wrote:
>
>
> On Fri, Jul 31, 2015 at 3:53 PM, Philip Reames
> <listmail at philipreames.com <mailto:listmail at philipreames.com>> wrote:
>
> Quoting from the google doc: "If we don’t know definition of some
> function, we assume that it will not call
> @llvm.invariant.group.barrier()."
> This part really really bugs me. We generally try to assume
> minimal knowledge of external functions (i.e. they can do
> anything) and this assumption would invert that. Is there a way
> we can rephrase the proposal which avoids the need for this? I'm
> not quite clear what this assumption buys us.
>
> This is because without it the optimization will be useless. For example:
> A* a = new A;
> a->foo(); //outline virtual
> a->foo();
>
> If we will assume that foo calls @llvm.invariant.barrier, then we will
> not be able to optimize the second call.
Why not? If foo calls @llvm.invariant.group.barrier, then it would have
to produce a new SSA value to accomplish anything which might effect the
second call. Given the call is on "a", not some return value from foo
or a global variable, we know that any SSA value created inside foo
isn't relevant. We should end up a with two loads of the vtable using
the same SSA value and the same invariant.group metadata. The later can
be forwarded from the former without issue right?
%a = ...;
%vtable1 = load %a + Y !invariant.group !0
%foo1 = load %vtable1 + X, !invariant.group !1
call %foo1(%a)
%vtable2 = load %a + Y !invariant.group !0 <-- Per state rules, this
value forwards from previous vtable load
%foo2 = load %vtable2 + X, !invariant.group !1
call %foo2(%a)
Philip
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