[LLVMdev] How doesn't llvm generate IR for logical negate operation

[zhi chen]

Yes, but my point is that there would be some overhead to do cast the <N x
i1> vectortype to an integerNty. Is there any good way to check not all of
these N bits in the vectortype are 0s?

On Fri, Apr 10, 2015 at 5:37 PM, Bruce Hoult <bruce at hoult.org> wrote:

> Sure, if you actually just want an i1 saying whether or not at least one
> bit is set to 1, then comparing against 0 is the right thing.
>
> That should end up generating a unary TST instruction on ISAs that have
> one.
>
> On Sat, Apr 11, 2015 at 12:29 PM, zhi chen <zchenhn at gmail.com> wrote:
>
>> Thanks, Bruce. So, what is the easiest way to check if there is any bit
>> set to 1 in a <N x i1> vector type? I used bitcast instruction to cast it
>> into "iN" first and them compare iN to 0. Do you have a better way to do
>> it? Thanks again.
>>
>> On Fri, Apr 10, 2015 at 5:22 PM, Bruce Hoult <bruce at hoult.org> wrote:
>>
>>> LLVM doesn't have a "logical neg" (or "not") operator. That's a C thing.
>>> Do a compare against 0 to create an i1 result, then zero extend the i1 to
>>> the size of integer result you want.
>>>
>>>
>>> On Sat, Apr 11, 2015 at 12:07 PM, zhi chen <zchenhn at gmail.com> wrote:
>>>
>>>> How can I generate LLVM IR for both logical NEG (!)? For example, if I
>>>> have Int32Ty a,
>>>>
>>>> For the bitwise NEG(~):
>>>>
>>>> c = ~a ;
>>>>
>>>> I can use the following API from LLVM:
>>>>
>>>> BinaryOperator *neg = BinaryOperator::CreateNeg(nbits, "bitwiseNEG", insertBefore);
>>>>
>>>> How, if I want to generate logical NEG:
>>>>
>>>> c = !a;
>>>>
>>>> what should I do for this?
>>>>
>>>> Thanks
>>>>
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>>>>
>>>
>>
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>
>
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