[LLVMdev] Help with definition of subregisters; spill, rematerialization and implicit uses
Quentin Colombet
qcolombet at apple.com
Fri Aug 15 10:01:11 PDT 2014
Hi Mikael,
On Aug 15, 2014, at 3:42 AM, Mikael Holmén <mikael.holmen at ericsson.com> wrote:
> Hi,
>
> I have a problem regarding sub-register definitions and LiveIntervals on
> our target. When a subregister is defined, other parts of the register
> are always left untouched - they are neither read or def:ed.
>
> It however seems that Codegen treats subregister definitions as somehow
> clobbering the whole register.
>
> The SSA-code looks like this after isel:
>
> (Reg0 and Reg1 are 16bit registers. Reg2, Reg3 and Reg4 are 32 bit
> registers with 16bit subregs, hi16 and lo16.)
>
> Reg0 = #imm0
> Reg1 = #imm1
>
> Reg2 = IMPLICIT_DEF
> Reg3 = INSERT_SUBREG Reg2, Reg0, hi16
> Reg4 = INSERT_SUBREG Reg3, Reg1, lo16
>
> After TwoAddressInstructionPass it becomes:
>
> Reg5:hi16<def,read-undef> = Reg0
> Reg5:lo16<def> = Reg1
>
> So, in my world this means a setting of the high 16 bits in Reg5 (not
> affecting the low part) followed by a setting of the low 16 bits (not
> affecting the high part). Is this how LLVM looks at it too?
Yes, it is.
>
> (What does the "read-undef" part really mean, since in my
> world, the setting of lo16 or hi16 does not in any way affect or
> access the other part of the register.)
read-undef means that we care only about the part we are defining.
Reg5:hi16<def,read-undef> means that whatever is set in Reg5, but hi16, we do not care.
Reg5:lo16<def> means that we do care about the value of Reg5:hi16.
Here is the exact definition:
/// IsUndef - True if this register operand reads an "undef" value, i.e. the
/// read value doesn't matter. This flag can be set on both use and def
/// operands. On a sub-register def operand, it refers to the part of the
/// register that isn't written. On a full-register def operand, it is a
/// noop. See readsReg().
>
> The question is: How should true subregister definitions be
> expressed so that they do not interfere with each other? See the
> detailed problem description below.
We do have a limitation in our current liveness tracking for sub-register. Therefore, I am not sure that is possible.
Conceptually, what you want is:
Reg5:hi16<def,read-undef>
Reg5:lo16<def,read-undef>
However, I guess this wouldn’t be supported, because it would mean that we do not care about the value of hi16 at the definition of Reg5:lo16. This is true, but after this definition we do care about hi16 and I am afraid read-undef does not convey the right information for the subsequent uses of Reg5.
You can give it a try and see how it goes.
>
> ---
>
> During RA it's decided Reg5 should be spilled and it's also decided Reg5
> can be rematerialized:
>
> "Value Reg5:0 at 5000r may remat from Reg5:hi16<def,read-undef> = mv_any16
> 32766"
>
> So it says Reg5 can be rematerialized by setting it's high part...
>
> We also get:
>
> reload: 5052r Reg5<def> = Load40FI <fi#2>
> rewrite: 5056r Reg5:lo16<def> = mv_nimm6_ar16 0
>
> So it inserts a reload of the full Reg5 prior to the setting of
> Reg5:lo16, because it thinks there is an implicit use of Reg5 when
> writing the low part??? This seems very weird to me.
>
> The decision is based on the fact that MachineOperand::readsReg()
> returns true:
>
> /// readsReg - Returns true if this operand reads the previous value
> of its
> /// register. A use operand with the <undef> flag set doesn't read its
> /// register. A sub-register def implicitly reads the other parts of the
> /// register being redefined unless the <undef> flag is set.
> ///
> /// This refers to reading the register value from before the current
> /// instruction or bundle. Internal bundle reads are not included.
> bool readsReg() const {
> assert(isReg() && "Wrong MachineOperand accessor");
> return !isUndef() && !isInternalRead() && (isUse() || getSubReg());
> }
>
> I don't get why we automatically should get an implicit use just
> because we are writing a subreg.
>
> Since Reg5:lo16 is defined with
>
> Reg5:lo16<def> = Reg1
>
> isUndef() will return false and getSubReg() true, and thus readsReg()
> true and the reload is inserted.
>
> Then we get
>
> *** Bad machine code: Instruction loads from dead spill slot ***
>
> because the spill slot has not been written.
This is weird. Any chance you could share a test case?
Thanks,
-Quentin
>
> Most grateful for any help,
> Mikael Holmén
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