[LLVMdev] Question regarding the x86 SBB instruction.

Michael Gottesman mgottesman at apple.com
Fri Jun 28 15:15:26 PDT 2013


(i.e. how said intrinsics are codegened as the IR level)

On Jun 28, 2013, at 3:14 PM, Michael Gottesman <mgottesman at apple.com> wrote:

> Look at the __builtin_addc* builtins in clang. I am currently working on an optimization which transforms said intrinsics into chains of ADCs/SBBs.
> 
> Michael
> 
> On Jun 28, 2013, at 5:51 AM, James Courtier-Dutton <james.dutton at gmail.com> wrote:
> 
>> Hi,
>> 
>> I have the x86 SBB instruction. how should I represent this in LLVM
>> IR.  (as part of a decompiler from binary to LLVM IR)
>> 
>> Pre-conditions:
>> %eax = 0xffffffff
>> %edx = 0xffffffff
>> %carry = 1
>> 
>> SBB %eax, %edx       // %edx is the destination doing %edx = %edx -
>> (%eax + carry)
>> JC  jump_destination1    // If the Carry flag is set, jump to jump_destination1
>> 
>> How do I represent this correctly in LLVM IR?
>> In the above case, the carry flag should be set by the SBB because:
>> %eax + carry == 0x100000000     (33 bits)  or 0x0 (32 bits)
>> %edx - (%eax + carry) == %edx   with Carry set.
>> 
>> If I use LLVM IR:
>> %eax2 = ADD i32 %eax1, %carry    (%eax2 == 0)
>> [%edx2,%carry] = llvm.ssub.with.overflow.i32 %edx1, %eax2    (carry ==
>> 0, but I want it to be 1)
>> 
>> So, the problem only occurs with the edge case of %eax == 0xffffffff
>> and carry == 1
>> 
>> Any ideas how I could make this work accurately in LLVM IR ?
>> I could put an if round it:
>> if ((%eax1 == 0xffffffff)) && (%carry1 == 1)) {
>>    %carry2 = 1
>> } else {
>> %eax2 = ADD i32 %eax1, %carry
>> [%edx2,%carry3] = llvm.ssub.with.overflow.i32 %edx1, %eax2
>> }
>> %carry4 = phi (%carry2, %carry3)      (true branch, else branch)
>> %edx3 = phi (%edx1, %edx2)
>> branch cond %carry4  jump_destination
>> 
>> Any better ideas?
>> 
>> James
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