[LLVMdev] mips16 hard float puzzle

reed kotler rkotler at mips.com
Mon Jan 7 18:07:00 PST 2013


For example:

/home/rkotler/llvm/install/bin/llc -mcpu=mips16 hf16_2.ll -march=mipsel 
-relocation-model=pic -o hf16_2.s -O3 -mips16-hard-float -soft-float


On 01/04/2013 07:45 PM, Eli Friedman wrote:
> On Fri, Jan 4, 2013 at 6:28 PM, reed kotler <rkotler at mips.com> wrote:
>> On 01/04/2013 06:08 PM, Eli Friedman wrote:
>>> On Fri, Jan 4, 2013 at 4:08 PM, reed kotler <rkotler at mips.com> wrote:
>>>> I'm working on mips16 hard float which at a first approximation is just
>>>> soft
>>>> float but calls different library routines. Those different library
>>>> routines
>>>> are just an implementation (in mips32 mode) of soft float using mips32
>>>> hardware instructions. This part is already done. (mips16 mode has no
>>>> floating point instructions).
>>>>
>>>> The next level of this that I am working on now is the ability to call
>>>> mips32 mode functions from mips16. This is needed for example to call the
>>>> math library (sin, cos), because those library
>>>> routines are mips32 functions.
>>>>
>>>> This has an interesting problem.
>>>>
>>>> The mips16 functions do not know what they are calling when it's an
>>>> external
>>>> function; i.e. it could be a mips32 or mips16.
>>>>
>>>> On mips32, floating point arguments, if they are argument 1 and argument
>>>> 2,
>>>> are passed in floating point registers. If the return type is floating
>>>> point, then it is returned in a floating point register.
>>>>
>>>> On mips 16, it is doing soft float essentially so the arguments are
>>>> passed
>>>> in integer registers.
>>>>
>>>> The way gcc mips16 does this is to call helper functions which do the
>>>> actual
>>>> call to the external function. The helper functions copy arg 1 and 2 into
>>>> fp
>>>> arg 1 and fp arg 2 and then do the actual call. So whether you are
>>>> calling
>>>> mips16 or mips32 from that point on does not matter.
>>>>
>>>> I'm simplifiying this a bit and you have to think about the mips abi to
>>>> understand how this all works but it does.
>>>>
>>>> The question I have is how to find the original prototype.
>>>>
>>>> In order to know if I need to call a helper function, and which helper
>>>> function to call, I need to know the return type and type of arguments 1
>>>> and
>>>> 2. I need to know this pre soft float lowering.
>>>>
>>>>   From what I can see, in the beginning of ISelLowering code, the DAG will
>>>> still reflect the original prototype. If I do a DAG.viewGraph() there in
>>>> the
>>>> debugger, it knows about the proper prototype (pre soft float lowering).
>>>>
>>>> It would have been cool to get the function class that corresponds to
>>>> this
>>>> call and get the arguments that way but I don't see how I can get it.
>>>>
>>>> Is looking at the DAG the only (or best) way to do find the function
>>>> prototype?
>>>>
>>>> I would be happy to add something to lowering calls methods but it was
>>>> not
>>>> clear how to do this too.
>>> You have to do this as part of call lowering: once the call is
>>> lowered, the type information is lost permanently.  It's not
>>> conceptually difficult to do as part of call lowering, though: in the
>>> MIPS-specific call lowering code, if you detect that a call requires
>>> an argument in an FP register, you just need to generate a call to the
>>> relevant helper rather than the function itself.
>>>
>>> -Eli
>> So just read the DAG in the beginning of MIPS-specific call lowering before
>> it gets modified?
> Take a look at CCValAssign etc. in MipsTargetLowering::LowerCall.
> (The DAG node for the callee doesn't have the necessary information in
> the general case, even though it might appear to work in simple
> cases.)
>
> -Eli

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