[LLVMdev] One question about two passes interaction
Robert Sandra
robert.sandra0712 at gmail.com
Fri Feb 22 23:10:12 PST 2013
Actually I tried ModulePass. It works exactly as what I expect.But I
found another problem. In ModulePass, it not only collects the
functions I create, it also treat some system function such as
'printf' as a function. I do not if I does something wrong. The codes
I use is as follows:
virtual bool runOnModule(Module &M) {
for (Module::iterator b = M.begin(), be = M.end(); b != be; ++b) {
Function *ff = dyn_cast<Function>(b);
errs() <<"testff0: "<<funcname_index<<'\n';
funcname[funcname_index++] = ff->getName();
}
return false;
}
My test source file:
void A(){}
void B(){printf("dada");}
void main(){A(); B();}
The ModulePass output is:
A
B
printf
main
Thanks.
Robert
---------------------------------------------------------------------------
Hi Robert,
Function passes are expected to have local behavior that can be scheduled
on a per-function basis in no particular order. To get the behavior you
want, you probably want to make "FunctionPass1" a Module pass and have it
iterate through all of the functions in the module.
You can find more information about passes and how to choose a type of pass
in the llvm documentation at http://llvm.org/docs/WritingAnLLVMPass.html.
Cheers,
Scott
On Sat, Feb 23, 2013 at 1:37 AM, Robert Sandra
<robert.sandra0712 at gmail.com
<http://lists.cs.uiuc.edu/mailman/listinfo/llvmdev>>wrote:
>* Hi all,*>**>* I am trying to run a case as follows:*>**>* FunctionPass1: try to get all function's names and store them to a global*>* array*>* FunctionPass2: get information from the global array*>* In FunctionPass2, I use getAnalysisUsage() to set that to run*>* FunctionPass2, FunctionPass1 should be executed first.*>**>* But according to the running result, I found that these two passes are*>* executing at the same time,*>* which means After FunctionPass1 iterate one function, then FunctionPass2*>* will be executed to iterate one function; then FunctionPass1 continues to*>* run, and then FunctionPass2....*>**>* While, what I expected is that the FunctionPass1 will complete first, then*>* FunctionPass2 will be executed. Am I understanding wrong?*>**>* Thanks.*>* Robert*>**>* _______________________________________________*>* LLVM Developers mailing list*>* LLVMdev at cs.uiuc.edu <http://lists.cs.uiuc.edu/mailman/listinfo/llvmdev> http://llvm.cs.uiuc.edu*>* http://lists.cs.uiuc.edu/mailman/listinfo/llvmdev*>**>
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