[LLVMdev] Convert fdiv - X/Y -> X*1/Y
Michael Ilseman
milseman at apple.com
Thu Aug 8 14:36:47 PDT 2013
On Aug 8, 2013, at 2:35 PM, Michael Ilseman <milseman at apple.com> wrote:
> Point #1 makes sense to me.
>
> For point #2, wouldn't that be somewhat orthogonal to the discussion, as it has/needs no knowledge that an IR-level transformation happened? Also, reciprocal-multiply will be the preferred option for many (most) backends if the IR says to do that. But, I suppose some backend might want to be allowed to do the reverse transformation if allowed by fast-math flags in IR, or fast-math mode in selection DAG.
>
Oh, I forgot about optimize-for-size, which might be a user who desires the reverse transformation.
> On Aug 8, 2013, at 2:23 PM, Chandler Carruth <chandlerc at google.com> wrote:
>
>>
>> On Thu, Aug 8, 2013 at 2:07 PM, Chad Rosier <chad.rosier at gmail.com> wrote:
>> On Thu, Aug 8, 2013 at 1:56 PM, Mark Lacey <mark.lacey at apple.com> wrote:
>>
>> On Aug 8, 2013, at 9:56 AM, Jim Grosbach <grosbach at apple.com> wrote:
>>
>>> Hi Chad,
>>>
>>> This is a great transform to do, but you’re right that it’s only safe under fast-math. This is particularly interesting when the original divisor is a constant so you can materialize the reciprocal at compile-time. You’re right that in either case, this optimization should only kick in when there is more than one divide instruction that will be changed to a mul.
>>
>> It can be worthwhile to do this even in the case where there is only a single divide since 1/Y might be loop invariant, and could then be hoisted out later by LICM. You just need to be able to fold it back together when there is only a single use, and that use is not inside a more deeply nested loop.
>>
>> Ben's patch does exactly this, so perhaps that is the right approach.
>>
>> Just to be clear of what is being proposed (which I rather like):
>>
>> 1) Canonical form is to use the reciprocal when allowed (by the fast math flags, whichever we decide are appropriate).
>> 2) The backend folds a single-use reciprocal into a direct divide.
>>
>> Did I get it right? If so, I think this is a really nice way to capture all of the potential benefits of forming reciprocals without pessimizing code where it isn't helpful.
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