[LLVMdev] How to duplicate a CallInst

[Bill Wendling]

On Jan 6, 2012, at 9:50 AM, Rafael Baldiati Parizi wrote:

> Hi,
> I have the following piece of code:
> %34 = fptosi float %33 to i32
> %35 = call i32 @function(i32 %34) nounwind
> 
> I would like of know how  can I duplicate the statement %35 ? , as follows:
> %34 = fptosi float %33 to i32
> %35 = call i32 @function(i32 %34) nounwind
> %36 = call i32 @function(i32 %34) nounwind
> 
> i.e, two instructions exactly equal.
> 
> Using clone, results in badref.

Did you insert the new call instruction it into the basic block?

> Moreover, how can I get the parameters of function?
> 
> This is my experimental code that not is running wich I need:
> for (BasicBlock::iterator Is = i->begin(), e = i->end(); Is != e; ++Is){ 
>  	    if(isa<CallInst>(*Is)){
>  	       CallInst *call = dyn_cast<CallInst>(&*Is);
>         Function* ft = call->getCalledFunction();
>        arguments = ????
>        CallInst *call2 = CallInst::Create(ft, arguments.begin(), arguments.end(), "", ++Is);
>     }
> }
> 
> 
Look at the call->getNumArgOperands() and call->getArgOperand() methods.

-bw