[LLVMdev] Surprising SCEV / Constant folding result
Chris Lattner
clattner at apple.com
Fri Dec 28 12:54:05 PST 2012
The SCCP pass should recognize the "always zero" case. It may be taught the identity that 0*x == 0.
-Chris
On Dec 28, 2012, at 5:28 PM, Jonas Wagner <jonas.wagner at epfl.ch> wrote:
> Hello,
>
> I've tested LLVM's ScalarEvolution analysis with different small examples. Here's a result that surprised me:
>
> void dont_optimize_away(int);
>
> void foo(int n) {
> int res = 0;
> for (int i = 0; i < n; ++i) {
> // The kind of things that SCEV can recognize is quite astounding...
> // It wins over gcc for this one.
> //res = res + i*i;
>
> // Also, the kind of things it can't recognize...
> res = res * i;
> }
> dont_optimize_away(res);
> }
>
> // Compile using
> $ clang -Wall -std=c99 -O2 -c clang_scev_surprise.c -S -o - -emit-llvm
>
> In this loop, the value res is always zero, yet LLVM does not optimize the loop away at -O2 (contrary to GCC). Is there a simple explanation for this?
>
> Is this a case that is general enough that we could include it in LLVM? It looks like something that ScalarEvolution could recognize. Or maybe we could constant-fold the particular pattern of having res = phi(0, res) as operand in a multiplication.
>
> Cheers,
> Jonas
>
> <clang_scev_surprise.c>
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