[LLVMdev] def-use chain for Instruction

[John Criswell]

On 5/7/11 11:14 AM, neda 8664 wrote:
> Hello all,
>
> I am a LLVM newer whowant to obtain the use-def chain for all 
> instruction of a sample code, for this purpose i use the following code.

Disassemble the LLVM bitcode for the file and see what the function 
looks like after optimization.  It's possible that the optimizations 
removed all the computation.

-- John T.

>
> ///////////////sample code://///////////////////////
> #include <stdlib.h>
> #include <stdio.h>
> #include <time.h>
>
> #define ARRAY_SIZE 5
>
>
> int main() {
>  int x, y, holder;
>  int k,z,f,i;
>   z=0;
>   f=0;
>   k=0;
>
>   for(x = 0; x < ARRAY_SIZE; x++)
>     for(y = 0; y < ARRAY_SIZE-1; y++)
>       if(x+y>10) {
>         holder = x+y;
>         k=z+1;
>     f=k+x;
>     if (i>k)
>         i=i+1;
>       }
> // return 1;
>
> }
>
> ////////////////////////pass code://///////////////////////////////
>   virtual bool runOnFunction(Function &F) {
>     std::vector<Instruction*> worklist;
>
>     for(inst_iterator I = inst_begin(F), E = inst_end(F); I != E; ++I){
>                 worklist.push_back(&*I);
>             }
>
>
>             for(std::vector<Instruction*>::iterator iter = 
> worklist.begin(); iter != worklist.end(); ++iter){
>                 Instruction* instr = *iter;
>                 errs() << "def: " <<*instr << "\n";
>                 for(Value::use_iterator i = instr->use_begin(), ie = 
> instr->use_end(); i!=ie; ++i){
>                     Value *v = *i;
>                     Instruction *vi = dyn_cast<Instruction>(*i);
>                     errs() << "\t\t" << *vi << "\n";
>                 }
>             }
>
>     return false;
>     }
>
> //////////////output///////////////
> def:   ret void
>
>
> but my output isn't my aim, can anyone help me?
>
> Thanks
>
>
>
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