[LLVMdev] Generating DFG or CDFG from C code

Andrew Trick atrick at apple.com
Fri Jul 1 09:22:24 PDT 2011


Unless someone else responds with "I've already done that" then you need to implement a pass. It's probably something you want to customize to your needs anyway.
-Andy

On Jun 30, 2011, at 11:50 PM, janarbek wrote:

> Hi Andrew,
> Thanks for the response. That helps a lot.
> 
> So that means I have to implement a pass, right ? Sorry for dumb question. I just started LLVM today.
> 
> 
>  
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> --- On Thu, 6/30/11, Andrew Trick <atrick at apple.com> wrote:
> 
> From: Andrew Trick <atrick at apple.com>
> Subject: Re: [LLVMdev] Generating DFG or CDFG from C code
> To: "janarbek" <canarbekmatay at yahoo.com>
> Cc: llvmdev at cs.uiuc.edu
> Date: Thursday, June 30, 2011, 10:51 PM
> 
> 
> On Jun 30, 2011, at 10:05 PM, janarbek wrote:
> 
>> 
>> Hi All,
>> I am reposting my question again since i think my question was not clear enough. 
>> I am wondering is it possible to generate Control Data Flow Graph from C using LLVM? or is it possible to get web-like structure of C code using llvm /
>> 
>> Thanks in advance,
>> Any comment suggestion would be appreciated.
>> 
>> Jan Ma.
>> 
>>  
>> 
>> ===========================================
>> 
>> 
>> --- On Thu, 6/30/11, janarbek <canarbekmatay at yahoo.com> wrote:
>> 
>> From: janarbek <canarbekmatay at yahoo.com>
>> Subject: Generating DFG or CDFG from C code
>> To: llvmdev at cs.uiuc.edu
>> Date: Thursday, June 30, 2011, 11:55 AM
>> 
>> Hi All,
>> 
>> I am new to LLVM. I want to generate a Dataflow graph or Control Dataflow graph from C code using LLVM. I have no idea how to do it in LLVM. I tried to use analysis and transform passes such as "-dot-cfg" but it doesn't give what I want. I want to generate a node for each operation in C code. 
>> 
>> Thanks in advance.
>> JM.
>> 
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> 
> I don't know if anyone has already done this, but some important pieces are there. See Dataflow.h and GraphWriter.h.
> 
> I think you'll run into a problem though because the value graph isn't fully connected. You have to walk the instruction stream looking for "roots".
> 
> -Andy

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