[LLVMdev] what's correct behavior for struct forward declarations?
Philip Guo
pg at cs.stanford.edu
Wed Feb 18 20:20:17 PST 2009
hi all,
i'm trying to use LLVM to compile some linux kernel code, and i noticed a
mismatch with gcc. here is a simplified test case:
struct foo {
int a;
int b;
int c;
};
static struct foo x; // 'forward' declaration?
int bar() {
printf("a: %d, b: %d, c: %d\n", x.a, x.b, x.c);
}
static struct foo x = {
.a = 1, .b = 2, .c = 3,
};
int main() {
bar();
return 0;
}
when this code is compiled with gcc and run, stdout prints "a: 1, b: 2, c:
3", which means that it takes the true declaration of x, initialized to 1,
2, 3. however, when it's compiled with llvm, llvm emits the following code
for x:
@x = internal global %struct.foo zeroinitializer ; <%struct.foo*>
[#uses=3]
which seems to me like it's taking the first declaration of x, which is a
forward declaration. is that the correct behavior? i believe that the
kernel developers intended for the second (real declaration) of x to be
visible, even in bar(), but that's not what's happening with llvm. is there
an easy workaround where i can get llvm to emit code initializing x to
{1,2,3}? thanks!
Philip
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