[LLVMdev] memory-to-memory instructions

Bagel bagel99 at gmail.com
Tue Aug 4 10:20:09 PDT 2009


It appears impossible to match memory-to-memory instructions (except for MOV). 
  The MSP430 supports these.  The following test case tries to match the 
pattern that generates "add.w &foo,&bar":

; RUN: llvm-as < %s | llc -march=msp430 -O3
target datalayout = "e-p:16:8:8-i8:8:8-i16:8:8-i32:8:8"
target triple = "msp430-generic-generic"
@foo = common global i16 0, align 2
@bar = common global i16 0, align 2
define void @x() nounwind {
	%1 = load i16* @bar
	%2 = load i16* @foo
	%3 = add i16 %2, %1
	store i16 %3, i16* @foo
	ret void
}

In the DAG matching code generated from the .td file there is :

if (N1.getOpcode() == ISD::ADD &&
     N1.hasOneUse()) {
    SDValue N10 = N1.getOperand(0);
    if (N10.getOpcode() == ISD::LOAD &&
        N10.hasOneUse() &&
        IsLegalAndProfitableToFold(N10.getNode(), N1.getNode(), N.getNode()) &&
        (Chain.getNode() == N10.getNode() || IsChainCompatible(Chain.getNode(),
            N10.getNode()))) {
... NEED TO MATCH ABOVE TO GENERATE MEMORY TO MEMORY PATTERN
    }

When debugged we get:
N10.hasOneUse() = 1
IsLegalAndProfitableToFold(N10.getNode(), N1.getNode(), N.getNode()) = 0
(Chain.getNode() == N10.getNode()) = 0
IsChainCompatible(Chain.getNode(), N10.getNode()) = 0

IsLegalAndProfitableToFold() rejects the pattern.  (Yes, I had OptLevel > None).

Before I dig further, can anyone answer the question: Does LLVM currently allow 
a matching a pattern with two loads?

thanks,
bagel



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