[LLVMdev] Type operator defenition
Kasra
kasra_n500 at yahoo.com
Wed Apr 1 13:54:47 PDT 2009
Hello,
When I was poking arround my llvm code, I realised that given a Type
there isn't a seperate container for the type operator functions.
Am I correct?
If so, wouldn't it make more sence to provide a container to put
the objects operator function in to reduce the overhead of
going through each non operator function to find the operator
function defined for it??
The reason for this seperate container is because most of languages
defined operators to manipulate objects.
For example each time there is an expression:
class int_t : some_custom_interger ;
int_t a, b;
...
a + b
we have to do : O(n)
const Type* ta = typeof("a");
for (int i=0, e=ta->getNumContainedTypes(); i<e; i++)
if( isa<Function>(*ta->getContainedType(i)) )
if( ta->getName() == "$operator +" )
call(function, valueof("a"), valueof("b") );
where else we could do something like: O(1)
enum { operator_add = 0, ... } ;
call( typeof("a")->operator[operator_add],
valueof("a"), valueof("b"));
With best regards,
-- Kasra
More information about the llvm-dev
mailing list