[LLVMdev] First time!

[aditya vishnubhotla]

hi prabhat,
how to extract the arguements(number of arguements
also) of the remarks statement(regarding
predecessors)?
 in your example i want to get my answer as 2!
thank you
aditya

--- Prabhat Kumar Saraswat
<prabhat.saraswat at gmail.com> wrote:

> Hi aditya,
> There are two ways to cound the number of
> predecessors for each basic block.
> 
> You can generate the control flow graph using the
> CallGraphScc pass with the
> granularity of basic block and can simply traverse
> the graph bottom up till
> the root. The number of nodes encountered would be
> the number of
> predecessors.
> 
> The second way would be to use the special ;preds
> marker in the llvm IR.
> Each basic block starts with this line which details
> the name of its
> predecessor blocks
> 
> for example
> 
> bb5:   ; preds bb2, bb3
> 
> thus bb5 is preceeded by bb2 and bb3.
> 
> but, one word of caution, even bb2 and bb3 can be
> preceeded by some other
> basic blocks, thus the count for bb5 (number of
> predecessors) won't be 2,
> but would be more (depends upon the predecessors of
> bb2 and bb3).
> 
> You can also try to utilize the branching info at
> the end of each basic
> block in llvmIR of the source.
> 
> I am working on something similar, do let me know if
> u need some specific
> information.
> 
> Regards
> Prabhat
> 
> 
> 
> On Dec 20, 2007 11:36 AM, aditya vishnubhotla
> <vvaditya12 at yahoo.com> wrote:
> 
> > Hi!
> >
> > I want to know
> >
> > How to count the number of predecessors for each
> basic
> > block?
> >
> > Thank You
> >
> >
> >
> >
> > 
>
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