[LLVMdev] Adding xadd instruction to X86

Chris Lattner sabre at nondot.org
Thu Dec 2 15:19:44 PST 2004


On Thu, 2 Dec 2004, Brent Monroe wrote:
> I'm trying to add the xadd instruction to the X86 back end.
> xadd r/m32, r32
> exchanges r/m32 and r32, and loads the sum into r/m32.  I'm
> interested in the case where the destination operand is a
> memory location.
>
> I've added the following entry to X86InstrInfo.td:
> def XADD32mr  : I<0x87, MRMDestMem,
>                 (ops i32mem:$src1, R32:$src2),

This looks fine.

>                 "xadd{l} {$src1|$src2}, {$src2|$src1}">;

I haven't checked this, but it's probably fine.

> The xadd is emitted for the intrinsic function:
> call int (<integer type>*, <integer type>)*
> %llvm.atomic_fetch_add_store(<integer type>* <pointer>,
>
> <integer type> <value>)
>
> I currently have the following code (PtrReg contains the
> pointer argument, ValReg the value arg, and TmpReg an unused
> register.):
>
> addDirectMem(BuildMI(BB, X86::XADD32mr, 4,
> TmpReg).addReg(TwoReg), ValReg);

This is the problem.  Try this:
 addDirectMem(BuildMI(BB, X86::XADD32mr, 4, TmpReg), ValReg).addReg(TwoReg);

In particular, you want to add the memory address before the other reg.

Another problem though, is that (without looking at manual) I think xadd
modifies the register value.  If this is the case, you will want to define
it as a "two-operand" instruction.  Making the above change should get the
assertion to go away though.

-Chris

-- 
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