On Mon, 16 Sep 2002 xli3 at uiuc.edu wrote:
> I don't understand in this line:
> if (CallInst* callInst = dyn_cast<CallInst>(&*inst)) {
> Where does 'inst' come from? What is inst and how should we
> get it? could you please clarify?
That 'inst' should be 'i'. The manual should be fixed.
Thanks,
-misha