On Mon, 16 Sep 2002 xli3 at uiuc.edu wrote: > I don't understand in this line: > if (CallInst* callInst = dyn_cast<CallInst>(&*inst)) { > Where does 'inst' come from? What is inst and how should we > get it? could you please clarify? That 'inst' should be 'i'. The manual should be fixed. Thanks, -misha