[llvm] [InstCombine] lshr (mul (X, 2^N + 1)), N -> add (X, lshr(X, N)) (PR #90295)
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llvm-commits at lists.llvm.org
Sun May 19 14:04:21 PDT 2024
================
@@ -1483,6 +1494,16 @@ Instruction *InstCombinerImpl::visitLShr(BinaryOperator &I) {
}
}
+ // lshr (mul nsw (X, 2^N + 1)), N -> add nsw (X, lshr(X, N))
+ if (match(Op0, m_OneUse(m_NSWMul(m_Value(X), m_APInt(MulC))))) {
+ if (BitWidth > 2 && (*MulC - 1).isPowerOf2() &&
+ MulC->logBase2() == ShAmtC) {
+ return BinaryOperator::CreateNSWAdd(
+ X, Builder.CreateLShr(X, ConstantInt::get(Ty, ShAmtC), "",
+ I.isExact()));
+ }
+ }
+
----------------
AtariDreams wrote:
> if (match(Op0, m_NUWMul(m_Value(X), m_APInt(MulC))) && BitWidth > 2 &&
> (*MulC - 1).isPowerOf2() && MulC->logBase2() == ShAmtC) {
> auto *BO0 = cast<OverflowingBinaryOperator>(Op0);
> // Look for a "splat" mul pattern - it replicates bits across each half
> // of a value, so a right shift is just a mask of the low bits:
> // lshr i[2N] (mul nuw X, (2^N)+1), N --> and iN X, (2^N)-1
> if (ShAmtC * 2 == BitWidth && BO0->hasNoUnsignedWrap())
> return BinaryOperator::CreateAnd(X, ConstantInt::get(Ty, *MulC - 2));
>
> // lshr (mul nuw (X, 2^N + 1)), N -> add nuw (X, lshr(X, N))
> if (Op0->hasOneUse() &&
> (BO0->hasNoUnsignedWrap() || &&BO0->hasNoSignedWrap())) {
> auto *NewAdd = BinaryOperator::CreateAdd(
> X,
> Builder.CreateLShr(X, ConstantInt::get(Ty, ShAmtC), "", I.isExact()));
> NewAdd->setHasNoSignedWrap(BO0->hasNoSignedWrap());
> NewAdd->setHasNoUnsignedWrap(BO0->hasNoSignedWrap());
> return NewAdd;
> }
> }
this eliminates the MulC >> ShiftC optimization
https://github.com/llvm/llvm-project/pull/90295
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