[llvm] Deduplication of cyclic PHI nodes (PR #86662)
Marek Sedláček via llvm-commits
llvm-commits at lists.llvm.org
Tue Apr 9 02:18:21 PDT 2024
================
@@ -114,6 +114,78 @@ static std::unique_ptr<Module> parseIR(LLVMContext &C, const char *IR) {
return Mod;
}
+TEST(Local, RemoveDuplicateCyclicPHINodes) {
+ LLVMContext C;
+
+ std::unique_ptr<Module> M = parseIR(C,
+ R"(
+ declare i64 @f() #0
+ declare void @f.2()
+
+ define void @f.3(i1 %flag1, i1 %flag2, i1 %flag3, i1 %flag4) {
+ bb:
+ %0 = call i64 @f()
+ br label %bb1
+
+ bb1:
+ %1 = phi i64 [ %7, %bb7 ], [ 5, %bb ]
+ %2 = phi i64 [ %8, %bb7 ], [ 5, %bb ]
+ br i1 %flag1, label %bb2, label %bb3
+
+ bb2:
+ br label %bb3
+
+ bb3:
+ %3 = phi i64 [ 1, %bb2 ], [ %1, %bb1 ]
+ %4 = phi i64 [ 1, %bb2 ], [ %2, %bb1 ]
+ br i1 %flag2, label %bb4, label %bb5
+
+ bb4:
+ br label %bb5
+
+ bb5:
+ %5 = phi i64 [ 2, %bb4 ], [ %3, %bb3 ]
+ %6 = phi i64 [ 2, %bb4 ], [ %4, %bb3 ]
+ br i1 %flag3, label %bb6, label %bb7
+
+ bb6:
+ br label %bb7
+
+ bb7:
+ %7 = phi i64 [ 3, %bb6 ], [ %5, %bb5 ]
+ %8 = phi i64 [ 3, %bb6 ], [ %6, %bb5 ]
+ br i1 %flag4, label %bb1, label %bb8
+
+ bb8:
+ call void @f.2()
+ ret void
+ }
+ )");
+
+ auto *GV = M->getNamedValue("f.3");
+ ASSERT_TRUE(GV);
+ auto *F = dyn_cast<Function>(GV);
+ ASSERT_TRUE(F);
+
+ for (Function::iterator I = F->begin(), E = F->end(); I != E;) {
+ BasicBlock *BB = &*I++;
+ EliminateDuplicatePHINodes(BB);
+ }
+
+ // No block should have more than 2 PHIs
----------------
mark-sed wrote:
The check is that there are less than 2 phis in each block, so without deduplication it fails.
And regarding why I have not used .ll test (which was also raised in the old review) is because using a unit test I can easily test that exactly this feature works and also it allows me to create a smaller test, where I don't have to worry about simplifycfg removing some parts.
I'll modify the test for enabled and disabled duplicate phis, but I think it does no harm to also keep this unit test, no?
https://github.com/llvm/llvm-project/pull/86662
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