[PATCH] D137461: [LoopInterchange] rewrite validDepInterchange() to ensure Lexicographically Order
MengXuan Cai via Phabricator via llvm-commits
llvm-commits at lists.llvm.org
Fri Nov 4 13:16:25 PDT 2022
Narutoworld created this revision.
Narutoworld added a reviewer: congzhe.
Narutoworld added projects: LLVM, LoopOptWG.
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Rewrite `validDepInterchange()` function to strictly follow Lexicographically Order.
Repository:
rG LLVM Github Monorepo
https://reviews.llvm.org/D137461
Files:
llvm/lib/Transforms/Scalar/LoopInterchange.cpp
Index: llvm/lib/Transforms/Scalar/LoopInterchange.cpp
===================================================================
--- llvm/lib/Transforms/Scalar/LoopInterchange.cpp
+++ llvm/lib/Transforms/Scalar/LoopInterchange.cpp
@@ -182,48 +182,21 @@
std::swap(DepMatrix[I][ToIndx], DepMatrix[I][FromIndx]);
}
-// Checks if no dependence exist in the dependency matrix in Row before Column.
-static bool containsNoDependence(CharMatrix &DepMatrix, unsigned Row,
- unsigned Column) {
- for (unsigned i = 0; i < Column; ++i) {
- if (DepMatrix[Row][i] != '=' && DepMatrix[Row][i] != 'S' &&
- DepMatrix[Row][i] != 'I')
+static bool isLexicographicallyPositive(std::vector<char> &DV) {
+ for (unsigned Level = 0; Level < DV.size(); ++Level) {
+ unsigned char Direction = DV[Level];
+ // Check DepVector from outter loop to inner loop
+ // Direction could be S, < , > , =, I
+ // Ignore S, =, I
+ // lexiographically positive means the first non (=, I, S) is <
+ if (Direction == '<')
+ return true;
+ if (Direction == '>')
return false;
}
return true;
}
-static bool validDepInterchange(CharMatrix &DepMatrix, unsigned Row,
- unsigned OuterLoopId, char InnerDep,
- char OuterDep) {
- if (InnerDep == OuterDep)
- return true;
-
- // It is legal to interchange if and only if after interchange no row has a
- // '>' direction as the leftmost non-'='.
-
- if (InnerDep == '=' || InnerDep == 'S' || InnerDep == 'I')
- return true;
-
- if (InnerDep == '<')
- return true;
-
- if (InnerDep == '>') {
- // If OuterLoopId represents outermost loop then interchanging will make the
- // 1st dependency as '>'
- if (OuterLoopId == 0)
- return false;
-
- // If all dependencies before OuterloopId are '=','S'or 'I'. Then
- // interchanging will result in this row having an outermost non '='
- // dependency of '>'
- if (!containsNoDependence(DepMatrix, Row, OuterLoopId))
- return true;
- }
-
- return false;
-}
-
// Checks if it is legal to interchange 2 loops.
// [Theorem] A permutation of the loops in a perfect nest is legal if and only
// if the direction matrix, after the same permutation is applied to its
@@ -238,7 +211,10 @@
char OuterDep = DepMatrix[Row][OuterLoopId];
if (InnerDep == '*' || OuterDep == '*')
return false;
- if (!validDepInterchange(DepMatrix, Row, OuterLoopId, InnerDep, OuterDep))
+ // Create temporary DepVector and swap OutterLoop vs InnerLoop
+ std::vector<char> Cur = DepMatrix[Row];
+ std::swap(Cur[InnerLoopId], Cur[OuterLoopId]);
+ if (!isLexicographicallyPositive(Cur))
return false;
}
return true;
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