[PATCH] D108733: Use std::less instead of operator < in less_first and less_second
Akira Hatanaka via Phabricator via llvm-commits
llvm-commits at lists.llvm.org
Wed Aug 25 15:09:44 PDT 2021
ahatanak created this revision.
ahatanak added reviewers: ldionne, bkramer.
ahatanak added a project: LLVM.
Herald added a subscriber: dexonsmith.
ahatanak requested review of this revision.
According to the standard, if p1 and p2 are both pointers, p1 < p2 and p2 < p1 can both be false in theory in some cases:
https://eel.is/c++draft/expr.rel#4.3
std::less<void> yields a implementation-defined strict total order over pointers:
https://eel.is/c++draft/comparisons.general
Repository:
rG LLVM Github Monorepo
https://reviews.llvm.org/D108733
Files:
llvm/include/llvm/ADT/STLExtras.h
Index: llvm/include/llvm/ADT/STLExtras.h
===================================================================
--- llvm/include/llvm/ADT/STLExtras.h
+++ llvm/include/llvm/ADT/STLExtras.h
@@ -1273,7 +1273,7 @@
/// compares less than the first component of another std::pair.
struct less_first {
template <typename T> bool operator()(const T &lhs, const T &rhs) const {
- return lhs.first < rhs.first;
+ return std::less<>()(lhs.first, rhs.first);
}
};
@@ -1281,7 +1281,7 @@
/// compares less than the second component of another std::pair.
struct less_second {
template <typename T> bool operator()(const T &lhs, const T &rhs) const {
- return lhs.second < rhs.second;
+ return std::less<>()(lhs.second, rhs.second);
}
};
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