[PATCH] D105921: [SCEV] Handle zero stride correctly in howManyLessThans
Philip Reames via Phabricator via llvm-commits
llvm-commits at lists.llvm.org
Tue Jul 13 13:32:00 PDT 2021
This revision was landed with ongoing or failed builds.
This revision was automatically updated to reflect the committed changes.
Closed by commit rG4df591b5c960: [SCEV] Handle zero stride correctly in howManyLessThans (authored by reames).
Changed prior to commit:
https://reviews.llvm.org/D105921?vs=358359&id=358413#toc
Repository:
rG LLVM Github Monorepo
CHANGES SINCE LAST ACTION
https://reviews.llvm.org/D105921/new/
https://reviews.llvm.org/D105921
Files:
llvm/lib/Analysis/ScalarEvolution.cpp
llvm/test/Analysis/ScalarEvolution/trip-count-unknown-stride.ll
Index: llvm/test/Analysis/ScalarEvolution/trip-count-unknown-stride.ll
===================================================================
--- llvm/test/Analysis/ScalarEvolution/trip-count-unknown-stride.ll
+++ llvm/test/Analysis/ScalarEvolution/trip-count-unknown-stride.ll
@@ -34,8 +34,8 @@
; Check that we are able to compute trip count of a loop without an entry guard.
-; CHECK-LABEL: Determining loop execution counts for: @foo2
-; CHECK: backedge-taken count is ((-1 + (%n smax %s)) /u %s)
+; CHECK: Determining loop execution counts for: @foo2
+; CHECK: backedge-taken count is ((-1 + (-1 * %s) + (1 umax %s) + (%n smax %s)) /u (1 umax %s))
; We should have a conservative estimate for the max backedge taken count for
; loops with unknown stride.
@@ -84,8 +84,8 @@
}
; Same as foo2, but with mustprogress on loop, not function
-; CHECK-LABEL: Determining loop execution counts for: @foo4
-; CHECK: backedge-taken count is ((-1 + (%n smax %s)) /u %s)
+; CHECK: Determining loop execution counts for: @foo4
+; CHECK: backedge-taken count is ((-1 + (-1 * %s) + (1 umax %s) + (%n smax %s)) /u (1 umax %s))
; CHECK: max backedge-taken count is -1
define void @foo4(i32* nocapture %A, i32 %n, i32 %s) {
@@ -108,7 +108,7 @@
; A more complex case with pre-increment compare instead of post-increment.
; CHECK-LABEL: Determining loop execution counts for: @foo5
-; CHECK: Loop %for.body: backedge-taken count is ((-1 + (-1 * %start) + (%n smax %start) + %s) /u %s)
+; CHECK: Loop %for.body: backedge-taken count is ((-1 + (-1 * %start) + (1 umax %s) + (%n smax %start)) /u (1 umax %s))
; We should have a conservative estimate for the max backedge taken count for
; loops with unknown stride.
Index: llvm/lib/Analysis/ScalarEvolution.cpp
===================================================================
--- llvm/lib/Analysis/ScalarEvolution.cpp
+++ llvm/lib/Analysis/ScalarEvolution.cpp
@@ -11653,6 +11653,30 @@
if (PredicatedIV || !NoWrap || isKnownNonPositive(Stride) ||
!loopIsFiniteByAssumption(L))
return getCouldNotCompute();
+
+ // We allow a potentially zero stride, but we need to divide by stride
+ // below. Since the loop can't be infinite and this check must control
+ // the sole exit, we can infer the exit must be taken on the first
+ // iteration (e.g. backedge count = 0) if the stride is zero. Given that,
+ // we know the numerator in the divides below must be zero, so we can
+ // pick an arbitrary non-zero value for the denominator (e.g. stride)
+ // and produce the right result.
+ // FIXME: Handle the case where Stride is poison?
+ auto wouldZeroStrideBeUB = [&]() {
+ // Proof by contradiction. Suppose the stride were zero. If we can
+ // prove that the backedge *is* taken on the first iteration, then since
+ // we know this condition controls the sole exit, we must have an
+ // infinite loop. We can't have a (well defined) infinite loop per
+ // check just above.
+ // Note: The (Start - Stride) term is used to get the start' term from
+ // (start' + stride,+,stride). Remember that we only care about the
+ // result of this expression when stride == 0 at runtime.
+ auto *StartIfZero = getMinusSCEV(IV->getStart(), Stride);
+ return isLoopEntryGuardedByCond(L, Cond, StartIfZero, RHS);
+ };
+ if (!isKnownNonZero(Stride) && !wouldZeroStrideBeUB()) {
+ Stride = getUMaxExpr(Stride, getOne(Stride->getType()));
+ }
} else if (!Stride->isOne() && !NoWrap) {
auto isUBOnWrap = [&]() {
// Can we prove this loop *must* be UB if overflow of IV occurs?
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