[PATCH] D105921: [SCEV] Handle zero stride correctly in howManyLessThans

Philip Reames via Phabricator via llvm-commits llvm-commits at lists.llvm.org
Tue Jul 13 11:19:51 PDT 2021


reames created this revision.
reames added reviewers: efriedma, mkazantsev, fhahn.
Herald added subscribers: bollu, hiraditya, mcrosier.
reames requested review of this revision.
Herald added a project: LLVM.

This is split from D105216 <https://reviews.llvm.org/D105216>, but the code is hoisted much earlier into the path where we can actually get a zero stride flowing through.  Some fairly simple proofs handle the cases which show up in practice.  The only test changes are the cases where we really do need a non-zero divider to produce the right result.


Repository:
  rG LLVM Github Monorepo

https://reviews.llvm.org/D105921

Files:
  llvm/lib/Analysis/ScalarEvolution.cpp
  llvm/test/Analysis/ScalarEvolution/trip-count-unknown-stride.ll


Index: llvm/test/Analysis/ScalarEvolution/trip-count-unknown-stride.ll
===================================================================
--- llvm/test/Analysis/ScalarEvolution/trip-count-unknown-stride.ll
+++ llvm/test/Analysis/ScalarEvolution/trip-count-unknown-stride.ll
@@ -35,7 +35,7 @@
 
 ; Check that we are able to compute trip count of a loop without an entry guard.
 ; CHECK: Determining loop execution counts for: @foo2
-; CHECK: backedge-taken count is ((-1 + (%n smax %s)) /u %s)
+; CHECK: backedge-taken count is ((-1 + (-1 * %s) + (1 umax %s) + (%n smax %s)) /u (1 umax %s))
 
 ; We should have a conservative estimate for the max backedge taken count for
 ; loops with unknown stride.
@@ -85,7 +85,7 @@
 
 ; Same as foo2, but with mustprogress on loop, not function
 ; CHECK: Determining loop execution counts for: @foo4
-; CHECK: backedge-taken count is ((-1 + (%n smax %s)) /u %s)
+; CHECK: backedge-taken count is ((-1 + (-1 * %s) + (1 umax %s) + (%n smax %s)) /u (1 umax %s))
 ; CHECK: max backedge-taken count is -1
 
 define void @foo4(i32* nocapture %A, i32 %n, i32 %s) {
Index: llvm/lib/Analysis/ScalarEvolution.cpp
===================================================================
--- llvm/lib/Analysis/ScalarEvolution.cpp
+++ llvm/lib/Analysis/ScalarEvolution.cpp
@@ -11653,6 +11653,30 @@
     if (PredicatedIV || !NoWrap || isKnownNonPositive(Stride) ||
         !loopIsFiniteByAssumption(L))
       return getCouldNotCompute();
+
+    // We allow a potentially zero stride, but we need to divide by stride
+    // below.  Since the loop can't be infinite and this check must control
+    // the sole exit, we can infer the exit must be taken on the first
+    // iteration (e.g. backedge count = 0) if the stride is zero.  Given that,
+    // we know the numerator in the divides below must be zero, so we can
+    // pick an arbitrary non-zero value for the denominator (e.g. stride)
+    // and produce the right result.
+    // FIXME: Handle the case where Stride is poison?
+    auto wouldZeroStrideBeUB = [&]() {
+      // Proof by contradiction.  Suppose the stride were zero.  If we can
+      // prove that the backedge *is* taken on the first iteration, then since
+      // we know this condition controls the sole exit, we must have an
+      // infinite loop.  We can't have a (well defined) infinite loop per
+      // check just above.
+      // Note: The (Start - Stride) term is used to get the start' term from
+      // (start' + stride,+,stride). Remember that we only care about the
+      // result of this expression when stride == 0 at runtime.
+      auto *StartIfZero = getMinusSCEV(IV->getStart(), Stride);
+      return isLoopEntryGuardedByCond(L, Cond, StartIfZero, RHS);
+    };
+    if (!isKnownNonZero(Stride) && !wouldZeroStrideBeUB()) {
+      Stride = getUMaxExpr(Stride, getOne(Stride->getType()));
+    }
   } else if (!Stride->isOne() && !NoWrap) {
     auto isUBOnWrap = [&]() {
       // Can we prove this loop *must* be UB if overflow of IV occurs?


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