[PATCH] D60730: Only use argv[0] as the main executable name if it exists.
Sean Silva via Phabricator via llvm-commits
llvm-commits at lists.llvm.org
Mon Apr 15 15:06:14 PDT 2019
This revision was automatically updated to reflect the committed changes.
Closed by commit rL358455: Only use argv[0] as the main executable name if it exists. (authored by silvas, committed by ).
Changed prior to commit:
https://reviews.llvm.org/D60730?vs=195242&id=195257#toc
Repository:
rL LLVM
CHANGES SINCE LAST ACTION
https://reviews.llvm.org/D60730/new/
https://reviews.llvm.org/D60730
Files:
llvm/trunk/lib/Support/Signals.cpp
Index: llvm/trunk/lib/Support/Signals.cpp
===================================================================
--- llvm/trunk/lib/Support/Signals.cpp
+++ llvm/trunk/lib/Support/Signals.cpp
@@ -131,8 +131,8 @@
// If we don't know argv0 or the address of main() at this point, try
// to guess it anyway (it's possible on some platforms).
std::string MainExecutableName =
- Argv0.empty() ? sys::fs::getMainExecutable(nullptr, nullptr)
- : (std::string)Argv0;
+ sys::fs::exists(Argv0) ? (std::string)Argv0
+ : sys::fs::getMainExecutable(nullptr, nullptr);
BumpPtrAllocator Allocator;
StringSaver StrPool(Allocator);
std::vector<const char *> Modules(Depth, nullptr);
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