[PATCH] D36486: [InstCombine] Don't fall back to only calling computeKnownBits if the upper bit of Add/Sub is demanded.
Craig Topper via Phabricator via llvmcommits
llvmcommits at lists.llvm.org
Tue Aug 8 13:39:10 PDT 2017
craig.topper created this revision.
Just create an all 1s demanded mask and continue recursing like normal. The recursive calls should be able to handle and all 1s mask do the right thing.
The only time we should care about knowing whether the upper bit was demanded is when we need to know if we should clear the NSW/NUW flags.
Now that we have a consistent path through the code for all cases, use KnownBits::computeForAddSub to compute the known bits at the end since we already have the LHS and RHS.
My larger goal here is to move the code that turns add into xor if only 1 bit is demanded and no bits below it are nonzero from InstCombiner::OptAndOp to here. This will allow it to be more general instead of just looking for 'add' and 'and' with constant RHS.
https://reviews.llvm.org/D36486
Files:
lib/Transforms/InstCombine/InstCombineSimplifyDemanded.cpp
Index: lib/Transforms/InstCombine/InstCombineSimplifyDemanded.cpp
===================================================================
 lib/Transforms/InstCombine/InstCombineSimplifyDemanded.cpp
+++ lib/Transforms/InstCombine/InstCombineSimplifyDemanded.cpp
@@ 396,38 +396,39 @@
/// If the highbits of an ADD/SUB are not demanded, then we do not care
/// about the high bits of the operands.
unsigned NLZ = DemandedMask.countLeadingZeros();
 if (NLZ > 0) {
 // Right fill the mask of bits for this ADD/SUB to demand the most
 // significant bit and all those below it.
 APInt DemandedFromOps(APInt::getLowBitsSet(BitWidth, BitWidthNLZ));
 if (ShrinkDemandedConstant(I, 0, DemandedFromOps) 
 SimplifyDemandedBits(I, 0, DemandedFromOps, LHSKnown, Depth + 1) 
 ShrinkDemandedConstant(I, 1, DemandedFromOps) 
 SimplifyDemandedBits(I, 1, DemandedFromOps, RHSKnown, Depth + 1)) {
+ // Right fill the mask of bits for this ADD/SUB to demand the most
+ // significant bit and all those below it.
+ APInt DemandedFromOps(APInt::getLowBitsSet(BitWidth, BitWidthNLZ));
+ if (ShrinkDemandedConstant(I, 0, DemandedFromOps) 
+ SimplifyDemandedBits(I, 0, DemandedFromOps, LHSKnown, Depth + 1) 
+ ShrinkDemandedConstant(I, 1, DemandedFromOps) 
+ SimplifyDemandedBits(I, 1, DemandedFromOps, RHSKnown, Depth + 1)) {
+ if (NLZ > 0) {
// Disable the nsw and nuw flags here: We can no longer guarantee that
// we won't wrap after simplification. Removing the nsw/nuw flags is
// legal here because the top bit is not demanded.
BinaryOperator &BinOP = *cast<BinaryOperator>(I);
BinOP.setHasNoSignedWrap(false);
BinOP.setHasNoUnsignedWrap(false);
 return I;
}

 // If we are known to be adding/subtracting zeros to every bit below
 // the highest demanded bit, we just return the other side.
 if (DemandedFromOps.isSubsetOf(RHSKnown.Zero))
 return I>getOperand(0);
 // We can't do this with the LHS for subtraction, unless we are only
 // demanding the LSB.
 if ((I>getOpcode() == Instruction::Add 
 DemandedFromOps.isOneValue()) &&
 DemandedFromOps.isSubsetOf(LHSKnown.Zero))
 return I>getOperand(1);
+ return I;
}
 // Otherwise just hand the add/sub off to computeKnownBits to fill in
 // the known zeros and ones.
 computeKnownBits(V, Known, Depth, CxtI);
+ // If we are known to be adding/subtracting zeros to every bit below
+ // the highest demanded bit, we just return the other side.
+ if (DemandedFromOps.isSubsetOf(RHSKnown.Zero))
+ return I>getOperand(0);
+ // We can't do this with the LHS for subtraction, unless we are only
+ // demanding the LSB.
+ if ((I>getOpcode() == Instruction::Add 
+ DemandedFromOps.isOneValue()) &&
+ DemandedFromOps.isSubsetOf(LHSKnown.Zero))
+ return I>getOperand(1);
+
+ // Otherwise just compute the known bits of the result.
+ bool NSW = cast<OverflowingBinaryOperator>(I)>hasNoUnsignedWrap();
+ Known = KnownBits::computeForAddSub(I>getOpcode() == Instruction::Add,
+ NSW, LHSKnown, RHSKnown);
break;
}
case Instruction::Shl: {
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