[llvm] r283892 - [cl] Don't print subcommand help when no subcommands present.

[Zachary Turner via llvm-commits]

Author: zturner
Date: Tue Oct 11 10:58:48 2016
New Revision: 283892

URL: http://llvm.org/viewvc/llvm-project?rev=283892&view=rev
Log:
[cl] Don't print subcommand help when no subcommands present.

Previously we would print

  USAGE: <exe> [subcommand] [options]

Even if no subcommands were present.  This changes the output
format to only print "[subcommand]" if there is at least one
subcommand.

Fixes llvm.org/pr30598

Patch by Serge Guelton

Modified:
    llvm/trunk/lib/Support/CommandLine.cpp

Modified: llvm/trunk/lib/Support/CommandLine.cpp
URL: http://llvm.org/viewvc/llvm-project/llvm/trunk/lib/Support/CommandLine.cpp?rev=283892&r1=283891&r2=283892&view=diff
==============================================================================
--- llvm/trunk/lib/Support/CommandLine.cpp (original)
+++ llvm/trunk/lib/Support/CommandLine.cpp Tue Oct 11 10:58:48 2016
@@ -1756,10 +1756,12 @@ public:
     if (!GlobalParser->ProgramOverview.empty())
       outs() << "OVERVIEW: " << GlobalParser->ProgramOverview << "\n";
 
-    if (Sub == &*TopLevelSubCommand)
-      outs() << "USAGE: " << GlobalParser->ProgramName
-             << " [subcommand] [options]";
-    else {
+    if (Sub == &*TopLevelSubCommand) {
+      outs() << "USAGE: " << GlobalParser->ProgramName;
+      if (Subs.size() > 2)
+        outs() << " [subcommand]";
+      outs() << " [options]";
+    } else {
       if (!Sub->getDescription().empty()) {
         outs() << "SUBCOMMAND '" << Sub->getName()
                << "': " << Sub->getDescription() << "\n\n";