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[Rafael Espindola]

> That should also be simplified as well.  the testcase in the example
> works because you know that "if *f is 0, that f is not null".

But we don't need __builtin_unreachable for that, do we? Can

void g(char);
int test(char *f) {
   g (*f);
   return f ? 1 : 0;
}

be simplified to "return 1"?

> -Chris

Cheers,
-- 
Rafael Avila de Espindola

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