[llvm-commits] [llvm] r42984 - /llvm/trunk/lib/Support/APFloat.cpp
Neil Booth
neil at daikokuya.co.uk
Mon Oct 15 08:00:55 PDT 2007
Author: neil
Date: Mon Oct 15 10:00:55 2007
New Revision: 42984
URL: http://llvm.org/viewvc/llvm-project?rev=42984&view=rev
Log:
Fast-track obviously over-large and over-small exponents during decimal->
integer conversion. In some such cases this makes us one or two orders
of magnitude faster than NetBSD's libc. Glibc seems to have a similar
fast path.
Also, tighten up some upper bounds to save a bit of memory.
Modified:
llvm/trunk/lib/Support/APFloat.cpp
Modified: llvm/trunk/lib/Support/APFloat.cpp
URL: http://llvm.org/viewvc/llvm-project/llvm/trunk/lib/Support/APFloat.cpp?rev=42984&r1=42983&r2=42984&view=diff
==============================================================================
--- llvm/trunk/lib/Support/APFloat.cpp (original)
+++ llvm/trunk/lib/Support/APFloat.cpp Mon Oct 15 10:00:55 2007
@@ -59,7 +59,7 @@
/* A tight upper bound on number of parts required to hold the value
pow(5, power) is
- power * 1024 / (441 * integerPartWidth) + 1
+ power * 815 / (351 * integerPartWidth) + 1
However, whilst the result may require only this many parts,
because we are multiplying two values to get it, the
@@ -70,8 +70,8 @@
const unsigned int maxExponent = 16383;
const unsigned int maxPrecision = 113;
const unsigned int maxPowerOfFiveExponent = maxExponent + maxPrecision - 1;
- const unsigned int maxPowerOfFiveParts = 2 + ((maxPowerOfFiveExponent * 1024)
- / (441 * integerPartWidth));
+ const unsigned int maxPowerOfFiveParts = 2 + ((maxPowerOfFiveExponent * 815)
+ / (351 * integerPartWidth));
}
/* Put a bunch of private, handy routines in an anonymous namespace. */
@@ -226,12 +226,19 @@
dddd.dddd[eE][+-]ddd
where the decimal point and exponent are optional, fill out the
- structure D. If the value is zero, V->firstSigDigit
- points to a zero, and the return exponent is zero. */
+ structure D. Exponent is appropriate if the significand is
+ treated as an integer, and normalizedExponent if the significand
+ is taken to have the decimal point after a single leading
+ non-zero digit.
+
+ If the value is zero, V->firstSigDigit points to a zero, and the
+ return exponent is zero.
+ */
struct decimalInfo {
const char *firstSigDigit;
const char *lastSigDigit;
int exponent;
+ int normalizedExponent;
};
void
@@ -243,6 +250,7 @@
D->firstSigDigit = p;
D->exponent = 0;
+ D->normalizedExponent = 0;
for (;;) {
if (*p == '.') {
@@ -270,8 +278,10 @@
while (*p == '0');
while (*p == '.');
- /* Adjust the specified exponent for any decimal point. */
+ /* Adjust the exponents for any decimal point. */
D->exponent += (dot - p) - (dot > p);
+ D->normalizedExponent = (D->exponent + (p - D->firstSigDigit)
+ - (dot > D->firstSigDigit && dot < p));
}
D->lastSigDigit = p;
@@ -2079,19 +2089,45 @@
/* Scan the text. */
interpretDecimal(p, &D);
+ /* Handle the quick cases. First the case of no significant digits,
+ i.e. zero, and then exponents that are obviously too large or too
+ small. Writing L for log 10 / log 2, a number d.ddddd*10^exp
+ definitely overflows if
+
+ (exp - 1) * L >= maxExponent
+
+ and definitely underflows to zero where
+
+ (exp + 1) * L <= minExponent - precision
+
+ With integer arithmetic the tightest bounds for L are
+
+ 93/28 < L < 196/59 [ numerator <= 256 ]
+ 42039/12655 < L < 28738/8651 [ numerator <= 65536 ]
+ */
+
if (*D.firstSigDigit == '0') {
category = fcZero;
fs = opOK;
+ } else if ((D.normalizedExponent + 1) * 28738
+ <= 8651 * (semantics->minExponent - (int) semantics->precision)) {
+ /* Underflow to zero and round. */
+ zeroSignificand();
+ fs = normalize(rounding_mode, lfLessThanHalf);
+ } else if ((D.normalizedExponent - 1) * 42039
+ >= 12655 * semantics->maxExponent) {
+ /* Overflow and round. */
+ fs = handleOverflow(rounding_mode);
} else {
integerPart *decSignificand;
unsigned int partCount;
/* A tight upper bound on number of bits required to hold an
- N-digit decimal integer is N * 256 / 77. Allocate enough space
+ N-digit decimal integer is N * 196 / 59. Allocate enough space
to hold the full significand, and an extra part required by
tcMultiplyPart. */
partCount = (D.lastSigDigit - D.firstSigDigit) + 1;
- partCount = partCountForBits(1 + 256 * partCount / 77);
+ partCount = partCountForBits(1 + 196 * partCount / 59);
decSignificand = new integerPart[partCount + 1];
partCount = 0;
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