[llvm-commits] CVS: llvm/lib/CodeGen/SelectionDAG/TargetLowering.cpp
Chris Lattner
sabre at nondot.org
Mon Nov 27 13:50:16 PST 2006
Changes in directory llvm/lib/CodeGen/SelectionDAG:
TargetLowering.cpp updated: 1.80 -> 1.81
---
Log message:
Fix the dag combiner bug corresponding to PR1014: http://llvm.org/PR1014 .
---
Diffs of the changes: (+8 -8)
TargetLowering.cpp | 16 ++++++++--------
1 files changed, 8 insertions(+), 8 deletions(-)
Index: llvm/lib/CodeGen/SelectionDAG/TargetLowering.cpp
diff -u llvm/lib/CodeGen/SelectionDAG/TargetLowering.cpp:1.80 llvm/lib/CodeGen/SelectionDAG/TargetLowering.cpp:1.81
--- llvm/lib/CodeGen/SelectionDAG/TargetLowering.cpp:1.80 Thu Nov 9 12:56:43 2006
+++ llvm/lib/CodeGen/SelectionDAG/TargetLowering.cpp Mon Nov 27 15:50:02 2006
@@ -363,20 +363,20 @@
return TLO.CombineTo(Op, Op.getOperand(0));
if ((DemandedMask & KnownZero2) == DemandedMask)
return TLO.CombineTo(Op, Op.getOperand(1));
+
+ // If all of the unknown bits are known to be zero on one side or the other
+ // (but not both) turn this into an *inclusive* or.
+ // e.g. (A & C1)^(B & C2) -> (A & C1)|(B & C2) iff C1&C2 == 0
+ if ((DemandedMask & ~KnownZero & ~KnownZero2) == 0)
+ return TLO.CombineTo(Op, TLO.DAG.getNode(ISD::OR, Op.getValueType(),
+ Op.getOperand(0),
+ Op.getOperand(1)));
// Output known-0 bits are known if clear or set in both the LHS & RHS.
KnownZeroOut = (KnownZero & KnownZero2) | (KnownOne & KnownOne2);
// Output known-1 are known to be set if set in only one of the LHS, RHS.
KnownOneOut = (KnownZero & KnownOne2) | (KnownOne & KnownZero2);
- // If all of the unknown bits are known to be zero on one side or the other
- // (but not both) turn this into an *inclusive* or.
- // e.g. (A & C1)^(B & C2) -> (A & C1)|(B & C2) iff C1&C2 == 0
- if (uint64_t UnknownBits = DemandedMask & ~(KnownZeroOut|KnownOneOut))
- if ((UnknownBits & (KnownZero|KnownZero2)) == UnknownBits)
- return TLO.CombineTo(Op, TLO.DAG.getNode(ISD::OR, Op.getValueType(),
- Op.getOperand(0),
- Op.getOperand(1)));
// If all of the demanded bits on one side are known, and all of the set
// bits on that side are also known to be set on the other side, turn this
// into an AND, as we know the bits will be cleared.
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