[LLVMbugs] [Bug 21289] New: Unrecognized indirect pack expansion when accessing value member
bugzilla-daemon at llvm.org
bugzilla-daemon at llvm.org
Wed Oct 15 11:57:24 PDT 2014
http://llvm.org/bugs/show_bug.cgi?id=21289
Bug ID: 21289
Summary: Unrecognized indirect pack expansion when accessing
value member
Product: clang
Version: 3.4
Hardware: PC
OS: Linux
Status: NEW
Severity: normal
Priority: P
Component: C++11
Assignee: unassignedclangbugs at nondot.org
Reporter: juchem at gmail.com
CC: dgregor at apple.com, llvmbugs at cs.uiuc.edu
Classification: Unclassified
The parameter packs in the code below are not recognized as unexpanded:
constant<size_type, 0>::type<Args>::value...
zero<Args>::value...
Tested in clang 3.4.1 from http://gcc.godbolt.org/ using -std=c++11:
http://goo.gl/R1soR4
It works in gcc 4.7 and up with -std=c++0x/-std=c++11.
-----------
#include <iostream>
#include <tuple>
#include <type_traits>
#include <utility>
template <typename T>
struct fixed {
template <typename> using type = T;
};
template <typename T>
struct fixed2 {
template <typename>
struct with {
using type = T;
};
};
template<typename T, T Value>
struct constant {
template <typename>
using type = std::integral_constant<T, Value>;
};
using size_type = std::size_t;
template <typename>
using zero = std::integral_constant<size_type, 0>;
template <typename... Args>
bool foo() {
using tuple = std::tuple<fixed<size_type>::type<Args>..., size_type>;
tuple t(constant<size_type, 0>::type<Args>::value..., 0);
return (&t == (tuple*)1);
}
template <typename... Args>
bool bar() {
using tuple = std::tuple<fixed<size_type>::type<Args>..., size_type>;
tuple t(zero<Args>::value..., 0);
return (&t == (tuple*)1);
}
template <typename... Args>
bool baz() {
using tuple = std::tuple<typename fixed2<size_type>::template
with<Args>::type..., size_type>;
tuple t(constant<size_type, 0>::type<Args>::value..., 0);
return (&t == (tuple*)1);
}
int main() {
std::cout << foo() << std::endl;
std::cout << foo<int, bool, double>() << std::endl;
std::cout << bar() << std::endl;
std::cout << bar<int, bool, double>() << std::endl;
std::cout << baz() << std::endl;
std::cout << baz<int, bool, double>() << std::endl;
};
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