[LLVMbugs] [Bug 20268] New: virtual deleted functions appear to be callable.
bugzilla-daemon at llvm.org
bugzilla-daemon at llvm.org
Wed Jul 9 13:47:22 PDT 2014
http://llvm.org/bugs/show_bug.cgi?id=20268
Bug ID: 20268
Summary: virtual deleted functions appear to be callable.
Product: clang
Version: trunk
Hardware: All
OS: All
Status: NEW
Severity: normal
Priority: P
Component: C++
Assignee: unassignedclangbugs at nondot.org
Reporter: mclow.lists at gmail.com
CC: dgregor at apple.com, llvmbugs at cs.uiuc.edu
Classification: Unclassified
#include <iostream>
#include <type_traits>
struct DeletedVirtualPublicDestructor { public: virtual
~DeletedVirtualPublicDestructor() = delete; };
struct DeletedVirtualProtectedDestructor { protected: virtual
~DeletedVirtualProtectedDestructor() = delete; };
struct DeletedVirtualPrivateDestructor { private: virtual
~DeletedVirtualPrivateDestructor() = delete; };
struct __two {char __lx[2];};
template <typename _Tp>
struct __is_destructor_wellformed {
template <typename _Tp1, typename _Tp2 =
decltype(std::declval<_Tp1&>().~_Tp1())>
static char __test (int);
template <typename _Tp1>
static __two __test (...);
static const bool value = sizeof(__test<_Tp>(12)) == sizeof(char);
};
int main () {
std::cout <<
__is_destructor_wellformed<DeletedVirtualPublicDestructor>::value << std::endl;
}
I expect this code to print '0', but it prints '1'.
Note that if I remove the "virtual" from DeletedVirtualPublicDestructor, it
prints '0'.
Tested with:
clang version 3.5.0 (trunk 212619)
Target: x86_64-apple-darwin13.3.0
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