[lldb-dev] RTTI does not work stable in LLDB.
Greg Clayton via lldb-dev
lldb-dev at lists.llvm.org
Mon Feb 6 10:22:32 PST 2017
I am looking at this now. I will let you know what I find.
Greg
> On Feb 6, 2017, at 10:00 AM, Roman Popov <ripopov at gmail.com> wrote:
>
> Yes, that was my thought.
>
> FYI, checked in GDB: it's working correctly on this testcase showing correct dynamic type in both cases.
>
> 2017-02-06 9:48 GMT-08:00 Greg Clayton <gclayton at apple.com <mailto:gclayton at apple.com>>:
> You have found a bug. It should be reporting this correctly but it isn’t. I verified it fails on MacOSX.
>
> Greg Clayton
>
>> On Feb 5, 2017, at 1:19 PM, Roman Popov via lldb-dev <lldb-dev at lists.llvm.org <mailto:lldb-dev at lists.llvm.org>> wrote:
>>
>> Hello,
>> I'm observing very strange LLDB behavior: it does not always shows a correct dynamic type when I ask for.
>>
>> Originally I was working with LLDB 3.9, but it looks like trunk version behaves the same strange way.
>>
>> I was able to capture this behavior in a small code snippet:
>>
>> #include <iostream>
>> #include <typeinfo>
>>
>> using namespace std;
>>
>> struct base_type { virtual ~base_type(){} };
>>
>> template <class T1, class T2, unsigned SIZE>
>> struct derived0 : base_type {};
>>
>> template <class T1, class T2>
>> struct derived1 : base_type {};
>>
>> int main(int argc, char ** argv) {
>>
>> base_type * bptr0 = new derived0<int, int, 1024>();
>> base_type * bptr1 = new derived1<int, int >();
>>
>> cout << typeid(*bptr0).name() << endl;
>> cout << typeid(*bptr1).name() << endl;
>>
>> return 0;
>> }
>>
>>
>> lldb --version
>> lldb version 5.0.0 (http://llvm.org/svn/llvm-project/lldb/trunk <http://llvm.org/svn/llvm-project/lldb/trunk> revision 293398)
>> clang revision 293398
>> llvm revision 293398
>>
>>
>> Testing in LLDB:
>> (lldb) break set --file main.cpp --line 22
>>
>> (lldb) expression -d no-run -- bptr1
>> (derived1<int, int> *) $2 = 0x0000000000614c40
>>
>> (lldb) expression -d no-run -- bptr0
>> (base_type *) $3 = 0x0000000000614c20
>>
>>
>> Can someone explain me why for bptr0 I dont get a derived0<int, int, 1024> * as I expected?
>>
>>
>> Thanks,
>> Roman
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>
>
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