[lldb-dev] RTTI does not work stable in LLDB.

[Roman Popov via lldb-dev]

Hello,
I'm observing very strange LLDB behavior: it does not always shows a
correct dynamic type when I ask for.

Originally I was working with LLDB 3.9, but it looks like trunk version
behaves the same strange way.

I was able to capture this behavior in a small code snippet:

#include <iostream>
#include <typeinfo>

using namespace std;

struct base_type {  virtual ~base_type(){} };

template <class T1, class T2, unsigned SIZE>
struct derived0 : base_type {};

template <class T1, class T2>
struct derived1 : base_type {};

int main(int argc, char ** argv) {

    base_type * bptr0 = new derived0<int, int, 1024>();
    base_type * bptr1 = new derived1<int, int >();

    cout << typeid(*bptr0).name() << endl;
    cout << typeid(*bptr1).name() << endl;

    return 0;
}


lldb --version
lldb version 5.0.0 (http://llvm.org/svn/llvm-project/lldb/trunk revision
293398)
  clang revision 293398
  llvm revision 293398


Testing in LLDB:
(lldb) break set --file main.cpp --line 22

(lldb) expression -d no-run --  bptr1
(derived1<int, int> *) $2 = 0x0000000000614c40

(lldb) expression -d no-run --  bptr0
*(base_type *) $3 = 0x0000000000614c20*


Can someone explain me why for bptr0 I dont get a  derived0<int, int, 1024>
* as I expected?


Thanks,
Roman
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