[Lldb-commits] [PATCH] D120101: [lldb] Fix (unintentional) recursion in CommandObjectRegexCommand

Jonas Devlieghere via Phabricator via lldb-commits lldb-commits at lists.llvm.org
Thu Feb 17 17:19:14 PST 2022

JDevlieghere added inline comments.

Comment at: lldb/source/Commands/CommandObjectRegexCommand.cpp:38
+    // Parse the number following '%'.
+    const size_t idx = std::atoi(str.c_str() + pos + 1);
mib wrote:
> Are we assuming that the number following `%` will always have a single digit ?
Added a comment to make it clear that atoi will parse until it encounters a character that's not a digit. 

Comment at: lldb/source/Commands/CommandObjectRegexCommand.cpp:50
+    const std::string replacement(replacements[idx]);
+    const size_t pattern_size = 1 + static_cast<size_t>(log10(idx) + 1);
+    str.replace(pos, pattern_size, replacement);
mib wrote:
> TIL but I think the exact formula is `floor(log10(num))+2` according to this https://stackoverflow.com/questions/61707231/why-is-log-base-10-used-in-this-code-to-convert-int-to-string
> I don't know if this formula has a name but if it does it would be great to add it as a comment above.
The formula you linked is to compute the size in bytes for the number, not the string length. Take `1` for example: floor(log10(1)) + 2 = 0 + 2  = 2.



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