[Lldb-commits] [PATCH] D88129: Add "break delete --disabled" to delete all currently disabled breakpoints
Dave Lee via Phabricator via lldb-commits
lldb-commits at lists.llvm.org
Wed Sep 23 12:16:54 PDT 2020
kastiglione added inline comments.
Comment at: lldb/source/Commands/Options.td:232
+ Desc<"Delete all breakpoints which are currently disabled. When using the disabled option "
+ "any breakpoints listed on the command line are EXCLUDED from deletion.">;
> kastiglione wrote:
> > To me, it's counter intuitive that `break delete --disabled 1` will not delete bp 1.
> The combination:
> (lldb) break delete --disabled 1
> could either mean
> 1) delete all breakpoints that are disabled AND breakpoint 1
> 2) delete all breakpoints that are disabled EXCEPT breakpoint 1
> 3) an error
> Of those interpretations, 1 and 3 don't seem very useful, but 2 does.
> This is particularly handy when you specify a breakpoint name, not a breakpoint. Just make breakpoints you don't want deleted DoNotDelete, then you can easily protect all those breakpoints.
> Note, your workaround would only be useful in this case if all the breakpoints named DoNotDelete are currently disabled. Otherwise you would have to remember which of the DoNotDelete breakpoints were disabled, enable them all, do the `delete --disabled` then only re-disable those that were originally disabled. Whereas if you can pass an exclude list you can just protect those breakpoints unconditionally regardless of their state.
> So while I agree this is a little odd, it's actually the only option that really makes sense, it's easy to document, and I don't think it's likely to cause mistakes.
why does the first interpretation not seem useful? If I'm deleting breakpoints, I might want to delete both disabled breakpoints and one or more specific breakpoints. To do that I would probably intuitively write `break delete --disabled OthersToDelete`.
Could the ambiguity be removed by adding another flag? `break delete --disabled --except DoNotDelete`?
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