[cfe-dev] The qualified name of a base class

[Sitvanit Ruah via cfe-dev]

Hello,
 I have the following classes in the input to my clang analyzer checker:

namespace bases{
  class base0{
  int x;
  ....};

  template <class T>
  class base1{
     private:
     int x;
     public:
      void print_member(){
         std::cout << x << std::endl;
    }
  };

  class derived : public base1<base0>{
  ...
  };

}

In my code in VisitRecordDecl(CXXRecordDecl decl) where decl is the
declaration of class "derived" I iterate over the bases of derived as
follows:

for (CXXBaseSpecifier *it = decl->bases->begin(); it!=decl->bases_end();
it++){
   QualType qual_type = it->getType();
   std::cout << qual_type.getAsString();
   }

   qual_type.getAsString() gives "base1<class bases::base 0>" for the base
of bases::derived. How can I get the full qualified name bases::base1<class
bases::base0>?

 The same happens when the derived and base classes are defined in
different namespaces.

 For example

 using namespace bases;
 namespace bases2{
   class derived2 : public base1<base0>

 }

 I still get only base1<class bases::base0> instead of bases::base1<class
bases::base0>.
 Note that for the template argument the full qualified name is given.

 ***The problem happens only when the base is a template. ***
Any idea how to solve this?
Thanks,
Sitvanit
-------------- next part --------------
An HTML attachment was scrubbed...
URL: <http://lists.llvm.org/pipermail/cfe-dev/attachments/20190522/ca527682/attachment.html>