[cfe-dev] How to find the source file, the called function is defined inside

[Georgiou, Andreas via cfe-dev]

Thank you for your answer.


I have found the solution in the Clang Devs archive. This is what I did


if (func_decl->hasBody()) //in order to get the definitions body and then locate it in the corresponding file
{
const FileEntry *file_entry = astContext->getSourceManager().getFileEntryForID(astContext->getSourceManager().getFileID(func_decl->getLocStart()));
string sourcepath = file_entry->getName();
const int idx = sourcepath.find_last_of("\\/");
if (std::string::npos != idx) //extract the filename from the entire path
{
  filename = sourcepath.substr(idx + 1);
}
}


My answer is just for the archive.

________________________________
From: Himanshu <himanshu at utexas.edu>
Sent: 22 July 2016 17:37:54
To: Georgiou, Andreas
Cc: cfe-dev at lists.llvm.org
Subject: Re: [cfe-dev] How to find the source file, the called function is defined inside

Hi,

You could use the getFilename() API by SourceManager. Get the function's startLoc and then pass it to the getFileName( ).

--
Himanshu

On Thu, Jul 21, 2016 at 6:53 PM, Georgiou, Andreas via cfe-dev <cfe-dev at lists.llvm.org<mailto:cfe-dev at lists.llvm.org>> wrote:

Hi all,

I have an ASTvisitor and when it visits a CallExpr node, if the expression is a function call I would like to retrieve the filename of the source code where the called function is defined within. Is it possible?

Thank you


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