[cfe-dev] CXXRecordDecl Name
Daniel Dilts
diltsman at gmail.com
Tue Jul 1 15:28:26 PDT 2014
There probably was an error, but I missed it. I am working on a clang-tidy
module, and sometimes it gets quite a bit of noise on the output.
On Tue, Jul 1, 2014 at 3:24 PM, Nikola Smiljanic <popizdeh at gmail.com> wrote:
> I thought no error was reported? I'm not surprised that getName returns an
> empty string for invalid code :)
>
>
> On Wed, Jul 2, 2014 at 8:21 AM, Reid Kleckner <rnk at google.com> wrote:
>
>> Why? The AST is invalid, and Clang diagnoses it.
>>
>> $ cat t.cpp
>> namespace N { };
>> struct N::A { };
>>
>> $ clang -c t.cpp
>> t.cpp:2:11: error: no struct named 'A' in namespace 'N'
>> struct N::A { };
>>
>>
>>
>> On Tue, Jul 1, 2014 at 3:13 PM, Nikola Smiljanic <popizdeh at gmail.com>
>> wrote:
>>
>>> Could you file a bug report for this Daniel?
>>>
>>>
>>> On Wed, Jul 2, 2014 at 3:02 AM, Daniel Dilts <diltsman at gmail.com> wrote:
>>>
>>>> I found my answer in 9p11 in the standard. Seems that without the
>>>> forward declaration it is invalid.
>>>>
>>>> If a class-head-name contains a nested-name-specifier, the
>>>> class-specifier shall refer to a class that was previously declared directly
>>>> in the class or namespace to which the nested-name-specifier refers, or in
>>>> an element of the inline namespace set of that namespace (i.e., not merely
>>>> inherited or introduced by a using-declaration), and the class-specifier
>>>> shall appear in a namespace enclosing the previous declaration.
>>>>
>>>>
>>>> On Tue, Jul 1, 2014 at 9:21 AM, Daniel Dilts <diltsman at gmail.com>
>>>> wrote:
>>>>
>>>>> If I have this code then everything works. If I get rid of the
>>>>> forward declaration, then any method returns an empty string. Is the
>>>>> forward declaration mandatory when defining the class like this?
>>>>>
>>>>> namespace N {
>>>>> class BaseClass1;
>>>>> }
>>>>> class N::BaseClass1 {
>>>>> public:
>>>>> BaseClass1(int i);
>>>>> BaseClass1(const BaseClass1 &right);
>>>>> virtual ~BaseClass1();
>>>>> BaseClass1 &operator=(const BaseClass1 &right);
>>>>> }
>>>>>
>>>>>
>>>>> On Mon, Jun 30, 2014 at 3:35 PM, Reid Kleckner <rnk at google.com> wrote:
>>>>>
>>>>>> Try getDeclName(), getNameAsString(), or others. getName() only
>>>>>> works if the name is a simple identifier:
>>>>>>
>>>>>> /// getName - Get the name of identifier for this declaration as a
>>>>>> StringRef.
>>>>>> /// This requires that the declaration have a name and that it be a
>>>>>> simple
>>>>>> /// identifier.
>>>>>> StringRef getName() const {
>>>>>> assert(Name.isIdentifier() && "Name is not a simple identifier");
>>>>>> return getIdentifier() ? getIdentifier()->getName() : "";
>>>>>> }
>>>>>>
>>>>>>
>>>>>>
>>>>>> On Mon, Jun 30, 2014 at 3:21 PM, Daniel Dilts <diltsman at gmail.com>
>>>>>> wrote:
>>>>>>
>>>>>>> I am attempting to get the name of a CXXRecordDecl that I have
>>>>>>> identified with an AST matcher. I am using Class->getName().str() to get
>>>>>>> the class name.
>>>>>>>
>>>>>>> namespace N {
>>>>>>> class SomeNonInterface {
>>>>>>> virtual void func1() = 0;
>>>>>>> virtual void func2() {}
>>>>>>> };
>>>>>>> }
>>>>>>>
>>>>>>> It works great for the above code. Gives me "SomeNonInterface" as
>>>>>>> the name.
>>>>>>>
>>>>>>> class N::BaseClass1 {
>>>>>>> public:
>>>>>>> BaseClass1(int i);
>>>>>>> BaseClass1(const BaseClass1 &right);
>>>>>>> virtual ~BaseClass1();
>>>>>>> BaseClass1 &operator=(const BaseClass1 &right);
>>>>>>> };
>>>>>>>
>>>>>>> For the above code it gives me "" as the name.
>>>>>>>
>>>>>>> How would I get the class name so that it works in all cases, even
>>>>>>> if the name in the declaration/definition is namespace qualified? Or...did
>>>>>>> I hit a case that isn't legal?
>>>>>>>
>>>>>>> _______________________________________________
>>>>>>> cfe-dev mailing list
>>>>>>> cfe-dev at cs.uiuc.edu
>>>>>>> http://lists.cs.uiuc.edu/mailman/listinfo/cfe-dev
>>>>>>>
>>>>>>>
>>>>>>
>>>>>
>>>>
>>>> _______________________________________________
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>>>>
>>>>
>>>
>>
>
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